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Solnce55 [7]
3 years ago
13

Which of the following measurements is expressed to three significant figures? 7.30 × 10–7 km 0.007 m 7077 mg 0.070 mm

Chemistry
1 answer:
Sonbull [250]3 years ago
4 0

7.30 x 10^-7 km. the others have 4 significant figures.

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1-Bromopropane is treated with each of the following reagents. Draw the major substitution product if the reaction proceeds in g
sammy [17]

Answer:

Explanation:

If we look at the structure of 1-Bromopropane; we will see that it is a derivative of alkane family by the the substitution of an alkyl group. The position of the Bromine in the propane is 1, making 1-Bromopropane  a primary alkyl-halide.

Primary alkyl - halide undergo SN2 mechanism. This nucleophilic reaction needs to be a strong alkyl halide , such as 1-Bromopropane used  otherwise it will result to a reactive mechanism if a weak electrophile is used.

However, the critical and the main objective here is to Draw the major substitution product if the reaction proceeds in good yield. If no reaction is expected or yields will be poor, draw the starting material in the box. If a charged product is formed, be sure to draw the counterion.

The attached diagrams portraying this notions is shown in the attached file below.

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2 years ago
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PilotLPTM [1.2K]

Answer:

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Explanation:

4 0
2 years ago
How does a sciences form a hypothesis
Oduvanchick [21]

they try to ask themselves why certain things happen and they try to make an educated guess of what will happen.

7 0
2 years ago
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7. A 26.4-ml sample of ethylene gas, C2H4, has a pres-sure of 2.50 atm at 2.5°C. If the
never [62]

Answer: 1.87 atm

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 2.50 atm

P_2 = final pressure of gas = ?

V_1 = initial volume of gas = 26.4 ml

V_2 = final volume of gas = 36.2 ml

T_1 = initial temperature of gas = 2.5^oC=273+2.5=275.5K

T_2 = final temperature of gas = 10^oC=273+10=283K

Now put all the given values in the above equation, we get:

\frac{2.50\times 26.4}{275.5}=\frac{P_2\times 36.2}{283}

P_2=1.87atm

The new pressure is 1.87 atm by using combined gas law.

6 0
3 years ago
Which of the following equations has the correct products and is balanced correctly for a reaction between Na3PO4 and KOH?
ASHA 777 [7]

The answer is: A) Na3PO4 + 3KOH → 3NaOH + K3PO4, because K retains the same charge throughout the reaction.

This chemical reaction is double displacement reaction - cations (K⁺ and Na⁺) and anions (PO₄³⁻⁻ and OH⁻) of the two reactants switch places and form two new compounds.  

Na₃PO₄ is sodium phosphate.  

KOH is potassium hydroxide.  

NaOH is sodium hydroxide.  

K₃PO₄ is potassium phosphate.  

According to the mass conservation law, there are same number of atoms on both side of balanced chemical reaction.

5 0
3 years ago
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