<span>. the same amount of work being done over a shorter period of time.</span>
The acceleration is 
Explanation:
This is a uniformly accelerated motion (constant acceleration), therefore we can apply the following suvat equation:

where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time
For the scooter in this problem, we have
u = 0 (it starts from rest)
v = 10.0 m/s is the final velocity
t = 4.0 s is the time interval
Solving for a, we find the acceleration:

Learn more about acceleration:
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Answer:
Explanation:
There is electric field between the plates whose value is given by the following expression
electric field E = V /d where V is potential between the plates and d is distance between them
E = 300 / 5 x 10⁻³
= 60 x 10³ N/c
Force on electron = q E where q is charge on the electron
F = 1.6 X 10⁻¹⁹ X 60 X 10³ = 96 X 10⁻¹⁶ N.
Acceleration a = force / mass
a = 96 x 10⁻¹⁶/ mass = 96 x 10⁻¹⁶ / 9.1 x 10⁻³¹
= 10.55 x 10¹⁵ m / s²
For midway , distance travelled
s = 2.5 x 10⁻³ m
s = 1\2 a t²
t = 
= 
t = .474 x 10⁻¹⁸ s
For striking the plate time is calculated as follows
t =
[/tex]
t = 0.67 x 10⁻¹⁸ s