Ask question

Ask question

All categories

3 years ago

7

Two vehicles approach an intersection: a truck moving eastbound at 16.0 m/s and an SUV moving southbound at 20.0 m/s. Suppose th

at the +x-axis is directed eastward and the +y-axis is directed northward. Find the magnitude of the velocity vector of the truck relative to the SUV.

1 answer:

mario62 [17]3 years ago

5 0

Answer:25.61 m/s

Explanation:

Given

truck is moving eastbound with a velocity of 16 m/s

Velocity of truck $v_t=16\hat{i}$

SUV is moving south with a velocity of 20 m/s

Velocity of SUV in vector form $v_s=-20\hat{j}$

Velocity of truck relative to the SUV

$v_{ts}=v_{t}-v_s$

$v_{ts}=16\hat{i}-(-20\hat{j})$

Magnitude of relative velocity is

$|v_{ts}|=\sqrt{16^2+20^2}$

$|v_{ts}|=25.61\ m/s$

You might be interested in

Power is measured in:

gogolik [260]

Power is the rate of doing work.
Its unit is joules/second.
That unit is used so often that a new word was adopted for it.

1 joule/sec = 1 watt

7 0

3 years ago

Pha của dao động làm hàm

KiRa [710]

Answer:

pha của dao động là hàm bậc nhất của thời gian.

6 0

3 years ago

An astronaut circling the earth at an altitude of 400 km is horrified to discover that a cloud of space debris is moving in the

elena-14-01-66 [18.8K]

One of the essential concepts to solve this problem is the utilization of the equations of centripetal and gravitational force.

From them it will be possible to find the speed of the body with which the estimated time can be calculated through the kinematic equations of motion. At the same time for the calculation of this speed it is necessary to clarify that this will remain twice the ship, because as we know by relativity, when moving in the same magnitude but in the opposite direction, with respect to the ship the debris will be double speed.

By equilibrium the centrifugal force and the gravitational force are equal therefore

$F_c = F_g$

$\frac{mv^2_{orbit}}{r} = \frac{GMm}{r^2}$

Where

m = mass spacecraft

v = velocity

G = Gravitational Universal Constant

M = Mass of earth

$r \rightarrow R+h \Rightarrow$ Radius of earth and orbit

Re-arrange to find the velocity

$\frac{mv^2_{orbit}}{r} = \frac{GMm}{r^2}$

$\frac{v^2_{orbit}}{r} = \frac{GM}{r^2}$

$v^2_{orbit}=\frac{GM}{r}$

$v_{orbit} = \sqrt{\frac{GM}{r}}$

$v_{orbit} = \sqrt{\frac{GM}{R+h}}$

Replacing with our values we have

$v_{orbit} = \sqrt{\frac{(6.67*10^{-11})(5.98*10^{24})}{6.37*10^6+0.4*10^6}}$

$v_{orbit} = 7676m/s$

From the cinematic equations of motion we have to

$t = \frac{d}{2v_{orbit}} \rightarrow$ Remember that the speed is double for the counter-direction of the trajectories.

Replacing

$t = \frac{29000m}{7676m/s}$

$t = 3.778s$

Therefore the time required is 3.778s

4 0

3 years ago

The Clean Air Act of 1963 was an improvement over the Air Pollution Control Act of 1955 because it _____.

Sveta_85 [38]

Was the first act to actually set emissions towards factory smoke and pollution

5 0

4 years ago

what is the momentum of a child and a wagon if the total mass of the child and wagon is 22kg and the velocity is 1.5m/s?

antoniya [11.8K]

Answer:

33 kg m/s

Explanation:

The momentum of an object is given by:

$p=mv$

where

m is the mass of the object

v is the velocity of the object

In this problem, the total mass of the child and the wagon is m =22 kg, while the velocity is v = 1.5 m/s, therefore the momentum is

$p=mv=(22 kg)(1.5 m/s)=33 kg m/s$

7 0

3 years ago