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olga55 [171]
3 years ago
7

Two vehicles approach an intersection: a truck moving eastbound at 16.0 m/s and an SUV moving southbound at 20.0 m/s. Suppose th

at the +x-axis is directed eastward and the +y-axis is directed northward. Find the magnitude of the velocity vector of the truck relative to the SUV.
Physics
1 answer:
mario62 [17]3 years ago
5 0

Answer:25.61 m/s

Explanation:

Given

truck is moving eastbound with a velocity of 16 m/s

Velocity of truck v_t=16\hat{i}

SUV is moving south with a velocity of 20 m/s

Velocity of SUV in vector form v_s=-20\hat{j}

Velocity of truck relative to the SUV

v_{ts}=v_{t}-v_s

v_{ts}=16\hat{i}-(-20\hat{j})

Magnitude of relative velocity is

|v_{ts}|=\sqrt{16^2+20^2}

|v_{ts}|=25.61\ m/s                                                  

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48 degress

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3 years ago
A battery with an emf of 24.0 V is connected to a resistive load. If the terminal voltage of the battery is 16.1 V and the curre
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Answer:

2.03 Ω

Explanation:

EMF: This can be defined as the potential difference of a cell when it is not delivering any current. The S.I unit of Emf is Volt.

The formula of emf is given as,

E = I(R+r)............................ Equation 1

Where E = Emf, I = current, R = External resistance, r = internal resistance.

Make r the subject of the equation

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Substitute into equation 3

r = (24-16.1)/3.9

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