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olga55 [171]
2 years ago
7

Two vehicles approach an intersection: a truck moving eastbound at 16.0 m/s and an SUV moving southbound at 20.0 m/s. Suppose th

at the +x-axis is directed eastward and the +y-axis is directed northward. Find the magnitude of the velocity vector of the truck relative to the SUV.
Physics
1 answer:
mario62 [17]2 years ago
5 0

Answer:25.61 m/s

Explanation:

Given

truck is moving eastbound with a velocity of 16 m/s

Velocity of truck v_t=16\hat{i}

SUV is moving south with a velocity of 20 m/s

Velocity of SUV in vector form v_s=-20\hat{j}

Velocity of truck relative to the SUV

v_{ts}=v_{t}-v_s

v_{ts}=16\hat{i}-(-20\hat{j})

Magnitude of relative velocity is

|v_{ts}|=\sqrt{16^2+20^2}

|v_{ts}|=25.61\ m/s                                                  

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TEA [102]

Answer:

1) x_total = 2.7 km=2700 m, 2)   t_total = 1926 s,  3)   v_avg = 1.40 m / s

Explanation:

1) To solve this uniform velocity problem, we must find the displacement of each part and add them.

        x_total = x₁ + x₂

        x_total = 0.7 + 2.0

        x_total = 2.7 km

2) how long does it take for this tour

         

truck

        v = x₁ / t₁

        t₁ = x₁ / v

        t₁ = 0.7 / 20

        t₁ = 0.035 h

Let's reduce the time to the SI system

         t₁ = 0.035 h (3600 s / 1h) = 126 s

when he is walking

         t₂ = 30 min (60 s / 1min) = 1800 s

the total time is

        t_total = t₁ + t₂

        t_total = 126 + 1800

        t_total = 1926 s

3) the average velocity is defined as the displacement in the inerval between time

        v_avg = x_total / t_total

         v_avg = 2700/1926

         v_avg = 1.40 m / s

8 0
3 years ago
A clock is designed that uses a mass on the end of a spring as a timing mechanism. If the oscillation time needed is exactly one
user100 [1]

Answer:

The value is  k  =  51.34 \  N/ m

Explanation:

From the question we are told that

   The  mass is  m =  1.3 \  kg

   The needed oscillation time is  T = 1 \ s  

 Generally the spring constant is mathematically represented  as

         k  =  \frac{4 \pi^2 * m }{ T^2}

=>      k  =  \frac{4* 3.142^2 * 1.3 }{ 1^2}

=>      k  =  51.34 \  N/ m

5 0
3 years ago
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