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2 years ago

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As the temperature of a liquid increases, the solubility of a liquid in that liquid A. increases. B. decreases. C. stays the sam

e. D. either increases or decreases, depending upon the liquid.

1 answer:

Rzqust [24]2 years ago

4 0

Should be A. increases

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What’s the answer please gelp

romanna [79]

Answer:

Option A. 1.8×10²⁴ molecules.

Explanation:

Data obtained from the question include:

Number of mole of methane = 3 moles

Number of molecules of methane =?

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02×10²³ molecules.

Thus, 1 mole of methane equally contains 6.02×10²³ molecules.

With the above information in mind, we can obtain the number of molecules in 3 moles of methane as follow:

1 mole of methane contains 6.02×10²³ molecules.

Therefore, 3 moles of methane will contain = 3 × 6.02×10²³ = 1.8×10²⁴ molecules.

Thus, 3 moles of methane contains 1.8×10²⁴ molecules.

4 0

3 years ago

Which ionic equation describes a redox reaction? A. Ag(+) + Cl- = AgCl B. 2H(+) + CO3(2-) = CO2 + H2O C. H(+) + OH(-) = H2O D. Z

Gennadij [26K]

<u>Answer:</u> The correct option is D. $Zn+Cu^{2+}\rightarrow Zn^{2+}+Cu$

<u>Explanation:</u>

Redox reaction is defined as the reaction in which oxidation and reduction take place simultaneously. It is known as the reaction in which the exchange of electrons takes place.

The oxidation reaction is defined as the reaction in which a chemical species loses electrons in a chemical reaction. It occurs when the oxidation number of a species increases.

A reduction reaction is defined as the reaction in which a chemical species gains electrons in a chemical reaction. It occurs when the oxidation number of a species decreases.

From the given ionic reactions:

$Zn+Cu^{2+}\rightarrow Zn^{2+}+Cu$

<u>On the reactant side: </u>

Oxidation number of Zn = 0

Oxidation number of Cu = +2

<u>On the product side: </u>

Oxidation number of Cu = 0

Oxidation number of Zn = +2

As the oxidation number of Zn is increasing from 0 to +2. Thus, it is getting oxidized. Similarly, the oxidation number of Cu is decreasing from +2 to 0. Thus, it is getting reduced. Therefore, forming a redox couple

Hence, the correct option is D. $Zn+Cu^{2+}\rightarrow Zn^{2+}+Cu$

6 0

2 years ago

Consider the reaction. PCl5(g)↽−−⇀PCl3(g)+Cl2(g) K=0.042 The concentrations of the products at equilibrium are [PCl3]=0.18 M and

tatyana61 [14]

<u>Answer:</u> The equilibrium concentration of $PCl_5$ is 1.285 M.

<u>Explanation:</u>

The chemical equation for the decomposition of phosphorus pentachloride follows:

$PCl_5(g)\rightleftharpoons PCl_3(g)+Cl_2(g)$

The expression for equilibrium constant is given as:

$K_c=\frac{[PCl_3][Cl_2]}{[PCl_5]}$

We are given:

$K_c=0.042$

$[PCl_3]=0.18M$

$[Cl_2]=0.30M$

The concentration of solid substances are taken to be 1. Thus, they do not appear in the equilibrium constant expression.

Putting values in above equation, we get:

$0.042=\frac{0.18\times 0.30}{[PCl_5]}$

$[PCl_5]=1.285$

Hence, the equilibrium concentration of $PCl_5$ is 1.285 M.

6 0

2 years ago

Use the periodic table, the table of common polyatomic ions, and the rules for naming ionic compounds to name the ionic compound

Elanso [62]

Aluminium oxide
Al3+ O2-

4 0

3 years ago

Read 2 more answers

In a galvanic cell,a oxidation occurs at the (name of electrode)b.the cathode is the (sign) electrodec.cations flow in solution

Tatiana [17]

Answer: a) anode

b) positive

c) cathode

d) anode to cathode

Explanation:

Galvanic cell is defined as a device which is used for the conversion of the chemical energy produces in a redox reaction into the electrical energy.

In the galvanic cell, the oxidation occurs at an anode which is a negative electrode and the reduction occurs at the cathode which is a positive electrode. Thus the electrons are produced at anode and travel towards cathode.

Due to loss of electrons at anode, positive charge in concentrated in anode and negative charge is concentrated in cathode. To balance these charges , positive ions or cations from salt bridge move towards cathode and negative ions or anions from salt bridge move towards anode.

The balanced two-half reactions will be:

Oxidation half reaction : $M(s)\rightarrow M^{n+}(aq)+ne^-$

Reduction half reaction : $X^{n+}(aq)+ne^-\rightarrow X(s)$

Thus the overall reaction will be,

$M(s)+X^{n+}(aq)\rightarrow M^{n+}(aq)+X(s)$

7 0

3 years ago