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gogolik [260]
2 years ago
5

Red light of wavelength 633 nm from a helium-neon laser passes through a slit 0.360 mm wide. The diffraction pattern is observed

on a screen 3.75 m away. Define the width of a bright fringe as the distance between the minima on either side.
(a) What is the width of the central bright fringe?(b) What is the width of the first bright fringe on either side of the central one?
Physics
1 answer:
Bumek [7]2 years ago
6 0

Answer:

a) 0.0130 m

b') w' = =6.46*10^{-3] m

Explanation:

given data:

\lambda of light = 633 nm

width of siit a =0.360 mm

distance from screen = 3.75 m

a) the first minima is located at

sin\theta = \frac{\lambda}{a}

              == \frac{633 *10^{-9}}{.360*10^{-3}}

           \theta = 0.100

y_1 = dtan\theta_1 = 3.75*tan(0.100) = 6.54 *10^{-3} m

with of central fringe  = 2y_1 = 2*6.54 *10^{-3} = 0.0130 m

b)

width of the first bright fringe on either side of the central one = w' = y_2 -y_1

calculation for y_2

sin\theta = 2\frac{\lambda}{a}

              = = 2*\frac{633 *10^{-9}}{.360*10^{-3}}

             \theta  = 2*0.100 = 0.200

y_2 = dtan\theta_1 = 3.75*tan(0.200) =0.0130 m

w' = 0.0130  -6.54 *10^{-3}

w' = =6.46*10^{-3] m

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coldgirl [10]

Answer:

See explanation

Explanation:

Favourite scientific discipline; Chemistry

Definition: Chemistry is the study of the composition, properties and uses of matter as well as the principles governing the changes that matter undergoes.

Source: New School Chemistry by Osei Yaw Ababio (2013)

Least Favourite Scientific Discipline: Botany

Definition: Botany is the study of plants, it includes the study of the structure and properties of plants, as well as the biochemical processes that go on in plants. It also involves the study of plant classification, plant diseases and interactions of plants with their environment.

Source: Encyclopedia Britiannica.

8 0
2 years ago
Which of the following is most like an indicator of a chemical change
qaws [65]

Answer:

methyl orange, methyl red,phenoptalin, merhy red

Explanation:

all this following are indicators use to check the end point of a reaction

5 0
3 years ago
John walks 1.00 km north, then turns right and walks 1.00 km east. His speed is 1.50 m/s during the entire stroll.a) What is the
avanturin [10]

Answer:

(a) 1.414 km

(b) 1.06 m/s

Explanation:

(a) For John:

Distance = 1 km north and then 1 km east

Speed = 1.5 m/s

total distance traveled = 1 + 1 = 2 km = 2000 m

Time taken to travel = Distance / speed

t = 2000 / 1.5 = 1333.3 seconds

Displacement = \sqrt{1^{2}+1^{2}}=1.414 km

(b) For jane :

Time is same as john = 1333.33 second

Distance = 1.414 km = 1414 m

Speed = distance / time = 1414 / 1333.33 = 1.06 m/s

3 0
3 years ago
Mercury has a radial acceleration of 3.96 × 10−2 m/s2 and its orbital period is T = 88 days. What is the radius of Mercury’s orb
Maslowich

Answer: 58,045,522,878.8 meters

Explanation:

Ok, the data we have is

Period = T = 88 days

Radial acceleration = ar = 3.96x10^-2 m/s^2

And we know that the equation for the radial acceleration is:

ar = v^2/r = r*w^2

Where v is the velocity. r is the radius and w is the angular velocity.

And we know that:

w = 2*pi*f

where f is the frequency, and:

T = 1/f.

Then we can write:

w = 2*pi/T

and our equation becomes:

ar = r*(2*pi/T)^2

Now we solve this for r.

First we need to use the same units in both equations, so we want to write T in seconds.

T = 88 days,

A day has 24 hours, and one hour has 3600 seconds:

T = 88*24*3600 s =7,603,200s

Then:

3.96x10^-2 m/s^2 = r*(2*3.14/7,603,200s)^2

r = (3.96x10^-2 m/s^2) /(2*3.14/7,603,200s)^2 = 58,045,522,878.8 meters

5 0
3 years ago
sound is a longitudinal wave, and its speed depends on the medium through which it propagates. in air, sound travels at 343 m/s
melomori [17]

The speed of the sound wave in the medium, given the data is 3900 m

<h3>Velocity of a wave </h3>

The velocity of a wave is related to its frequency and wavelength according to the following equation:

Velocity (v) = wavelength (λ) × frequency (f)

v = λf

With the above formula, we can obtain the speed of the sound wave. Details below:

<h3>How to determine speed of the sound wave</h3>

The speed of the wave can be obtained as illustrated below:

  • Frequency (f) = 600 Hz
  • Wavelength (λ) = 6.5 m
  • Velocity (v) =?

v = λf

v = 6.5 × 600

v = 3900 m

Thus, the speed of the sound wave in the medium is 3900 m

Learn more about wave:

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8 0
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