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gulaghasi [49]
3 years ago
10

Select the correct answer.

Physics
1 answer:
aleksklad [387]3 years ago
4 0
A. Alternating current
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A student of mass 63.4 kg, starting at rest, slides down a slide 21.2 m long, tilted at an angle of 26.1° with respect to thehor
Vera_Pavlovna [14]

Answer:

fr = 65.46 N ,   a = 8.74 m / s²  and  vf = 19.25 m / s

Explanation:

We write a reference system with an axis parallel to the slide and gold perpendicular axis, in this system we decompose the weight

      sin 21.2 = Wx / W

      cos21.2 = Wy / W

      Wx = W sin21.2

      Wy = W cos 21.2

We form Newton's equations

X axis

      Wx -fr = m a

Y Axis

     N- Wy = 0

     N = Wy

     fr = μ N

     fr = μ (W cos 21.2)

     fr = 0.113 63.4 9.8 cos 21.2

     fr = 65.46 N

We replace and calculate the acceleration

     W sin 21.2 - μ W cos 21.2 = m a

     a = g (sin21.2 - μ cos 21.2)

     a = 9.8 (without 21.2 - 0.113 cos 21.2)

     a = 8.74 m / s²

This acceleration is along the slope of the slide, so we can calculate the distance

     d = 21.2 m

     vf² = v₀² + 2 a d

    vf² = 0 + 2 a d

    vf = √(2 8.74 21.2)

    vf = √ (370,576)

    vf = 19.25 m / s

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