The concentration of carbon monoxide at equilibrium is 0.209 M.
<h3>Concentration of each gas</h3>
CO2 = 2 mol/5 L = 0.4
H2 = 1.5 mol/5L = 0.3
<h3>ICE table</h3>
Create ICE table as shown below
CO2(g) + H2(g) ↔ CO(g) + H2O(g)
I 0.4 0.3 0 0
C - x - x x x
E 0.4 - x 0.3 - x x x
Kc = [CO][H₂O] / [CO₂][H₂]
2.5 = (x²)/(0.4 - x)(0.3 - x)
x² = 2.5(0.4 - x)(0.3 - x)
x² = 2.5(0.12 - 0.7x + x²)
x² = 0.3 - 1.75x + 2.5x²
0 = 1.5x² - 1.75x + 0.3
solve the quadratic equation using formula method;
x = 0.209
Thus, the concentration of carbon monoxide at equilibrium is 0.209 M.
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AH1 = m * c1 * AT1 calculate this for ice (-25C to 0C) AH2 = AHfus(1 mole)=6.01 kJ = 6010 J AH3 = m *c3 * AT3 calculat this for water (0C to 100C) AH4 = AHvap(1mole)=40.67 kJ = 40670 J AH5= m * c5 * AT5 calculate this for steam (100C to 125C)
Sum ---- AH1+AH2+AH3+AH4+AH5
Data m=18g (1mole water)
c1=specific heat ice= 2.09 J/g K c3=specific heat water= 4.18 J/g K c5=specific heat steam= 1.84 J/g K
AT = (Tend - Tinitial) as this is a difference between temperatures it doesn't matter the units Celsius or Kelvin. Kelvin (K)=Celsius (C)+273.15
AT1 = 0C - (-25C)= 25C= 273.15K - 248.15K= 25K AT3= 100C - 0C = 100C= 100K AT5= 125C - 100C= 25C=25K
To solve this problem,
we must first examine the chemical formula of an alkene (CnH2n) and notice that
there are 2 H atoms for every 1 C atom.
<span>
Therefore this means that we can calculate the
weight percent of Hydrogen (H) using the molecular formula: </span>
<span>wt% H2 = 2n * (1.0g/mol H)/[2n*(1.0g/mol H) + n*(12.0g/mol
C)) x 100 = 14.3 wt% H
So for any alkene with mass of 0.561g, this contains
(0.143)x(0.561g) = 0.080 g H
Now, we calculate the number of moles of H this is by
dividing with the molar mass:
moles H = (0.080g H) / (1.00 g/mol H) = 0.08 moles H.
We know that there are 0.5 moles of water per mole of hydrogen,
therefore the moles of H2O formed is:
moles H2O = 0.5 * moles H = 0.5 * (0.08) = 0.04 moles H2O</span>
Answer:
<span>0.04 moles water</span>
Answer:
- "Newton’s viscosity law’s states that, the shear stress between adjacent fluid layers is proportional to the velocity gradients between the two layers".
- A non-Newtonian fluid is a fluid which the relationship between the shear stress and the velocity gradient is not properly defined by the Newton's viscosity law, thus, the behavior is not lineal but potential.
Explanation:
Hello, here the answers:
- "Newton’s viscosity law’s states that, the shear stress between adjacent fluid layers is proportional to the velocity gradients between the two layers" (taken from Kundu, P. K., Cohen, I. M., & Dowling, D. R. (2012). Fluid mechanics.), thus, it means that when you have a fluid with an acting-on-it share stress (an external force which move the fluid), the related velocity gradient (variation or change in velocity) at which the layers are moving are related as:
Whereas is the shear stress, is the viscosity and the differential accounts for the change in the velocity in the arbitrary coordinate.
- A non-Newtonian fluid is a fluid which the relationship between the shear stress and the velocity gradient is not properly defined by the Newton's viscosity law, thus, the behavior is not lineal but potential, based on:
Whereas accounts for a decreasing or increasing behavior of the shear stress.
Best regards.