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3 years ago

Plutonium has a half life of 2.4 × 104 years. How long does it take for 99.0% of the plutonium to decay?

Physics

1 answer:

natali 33 [55]3 years ago

8 0

Answer:

252 years

Explanation:

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A water wheel is a example of

Kisachek [45]

a machine for converting the energy of falling water into useful forms of power and it is also known as a watermill

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3 years ago

8. At what position does the mass have the greatest acceleration?

gulaghasi [49]

Answer:

Option (e)

Explanation:

If a mass attached to a spring is stretched and released, it follows a simple harmonic motion.

In simple harmonic motion, velocity of the mass will be maximum, kinetic energy is maximum and acceleration is 0 at equilibrium position (at 0 position).

At position +A, mass will have the minimum kinetic energy, zero velocity and maximum acceleration.

Therefore, Option (e) will be the answer.

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2 years ago

A box has a mass of 150kg and the surface area of the bottom of the box is :

charle [14.2K]

Answer:

Pressure = 100 Pascals

Explanation:

$pressure = \frac{force}{area} \\ = \frac{150 \times 10}{15} \\ = \frac{1500}{15} \\ = 100 pa$

3 0

3 years ago

An 8-passenger Learjet has a force of gravity of 6.6x10^4 [down] acting on it as it travels at a constant velocity of 6.4x10^2 k

IgorC [24]

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7 0

3 years ago

A ball of moist clay falls 17.3 m to the ground. It is in contact with the ground for 24.0 ms before stopping. (a) What is the a

gizmo_the_mogwai [7]

Answer:

Acceleration, $767.08\ m/s^2$

Explanation:

Given that,

Height from a ball falls the ground, h = 17.3 m

It is in contact with the ground for 24.0 ms before stopping.

We need to find the average acceleration the ball during the time it is in contact with the ground.

Firstly, find the velocity when it reached the ground. So,

$v^2=u^2+2ah$

u = initial velocity=0 m/s

a = acceleration=g

$v=\sqrt{2gh} \\\\v=\sqrt{2\times 9.8\times 17.3} \\\\v=18.41\ m/s$

It is in negative direction, u = -18.41 m/s

Let a is average acceleration of the ball. Consider, v = and u = -18.41 m/s.

$a=\dfrac{v-u}{t}\\\\a=\dfrac{0-18.41}{24\times 10^{-3}}\\\\a=767.08\ m/s^2$

So, the average acceleration of the ball during the time it is in contact is $767.08\ m/s^2$ .

4 0

3 years ago