Just multiply the "1.0 m/s" by ' 1 ' a few times. (Remember that a fraction with the same quantity on top and bottom is equal to ' 1 ' .)
(1.0 m/sec) · (1 km/1000 m) · (60 sec/min) · (60 min/hr) =
(1.0 · 60 · 60 / 1,000) (m · km · sec · min / sec · m · min · hr) =
(3,600 / 1,000) (km / hr) =
3.6 km/hr .
Answer:
66.98 db
Explanation:
We know that
L_T= Total signal level in db
n= number of sources
L_S= signal level from signal source.
= 66.98 db
Answer:
the SI base unit of electrical current
They may be changed because they may find evidence of some thing that will change their perspective on things.
Answer: 20.2 m/s
Explanation:
From the question above, we have the following data;
M1 = 800kg
M2 = 1200kg
V1 = 13m/s
V2 = 25m/s
U (common velocity) =?
M1V1 + M2V2 = (M1 + M2). U
(800*13) + (1200*25) = (800+1200) * U
10400 + 30000 = 2000u
40400 = 2000u
U = 40400 / 2000
U = 20.2 m/s
