C. 7
The mass number of this atom is the number of protons and the number of neutrons combined, which in this case would be 3+4 or 7.
Hope this helps.
Answer:
Explanation:
x = 3 Cos (4πt + π/5)
(a) Substitute t = 3 s
x = 3 Cos (12π + π/5)
x = 3 (0.82) = 2.46 m
(b) Velocity, v = dx/dt
v = 3 (-1)(4π) Sin(4πt + π/5)
Substitute t = 3 s
v = - 37.68 Sin(12π + π/5)
v = - 37.68 (0.572)
v = - 21.55 m/s
(c) Acceleration, a = dv/dt
a = 3 (-1)(4π)(4π) Cos(4πt + π/5)
Substitute t = 3 s
a = - 473.26 (0.82)
a = - 388.21 m/s²
(d) Phase = 4πt + π/5
Substitute t = 3 s
Phase = 12 π + π/5 = 38.308 rad
(e) ω = 4π
so, 2πf = 4π
f = 2 Hz
(f) T = 1 / f = 1 / 2 = 0.5 second
Explanation:
The liquid contains only one element. -The liquid is a pure substance. The number at the end of an isotope's name is the -mass number. While looking at xenon (Xe) on the periodic table, a student needs to find an element with a smaller atomic mass in the same group.
Answer:
The answer is 12.67 TMU
Explanation:
Recall that,
worker’s eyes travel distance must be = 20 in.
The perpendicular distance from her eyes to the line of travel is =24 in
What is the MTM-1 normal time in TMUs that should be allowed for the eye travel element = ?
Now,
We solve for the given problem.
Eye travel is = 15.2 * T/D
=15.2 * 20 in/24 in
so,
= 12.67 TMU
Therefore, the MTM -1 of normal time that should be allowed for the eye travel element is = 12.67 TMU