So I'm not totally sure but I got -15.32
So sorry if it's wrong!!
10m/s
32m/s
83m/s
None of these
Answer :
C
Solution :
At any instant x2+y2=52
Differentiating w.r.t. time 2xxdt+2ydydt=0
Here dxdt=2,dydt=u⇒u=83m/s
Yes, the rules of scientific notation are:
1. All non-zero digits are significant
2. Zeros in between non-zeros are significant.
3. Zeros to the left of the first non-zero number are NOT significant.
4. Zeros to the right of non-zero numbers are significant IF a decimal point is present.
P.S: if you need help with sig fig rounding, let me know.
Answer:
The length of the line segment UV is 76 units
Step-by-step explanation:
In a triangle, the line segment joining the mid-points of two sides is parallel to the third side and equal to half its length
In Δ ONT
∵ U is the mid-point of ON
∵ V is the mid-point of TN
→ That means UV is joining the mid-points of two sides
∴ UV // OT
∴ UV = OT
∵ UV = 7x - 8
∵ OT = 12x + 8
∴ 7x - 8 = (12x + 8)
→ Multiply the bracket by
∵ (12x + 8) = (12x) + (8) = 6x + 4
∴ 7x - 8 = 6x + 4
→ Add 8 to both sides
∴ 7x - 8 + 8 = 6x + 4 + 8
∴ 7x = 6x + 12
→ Subtract 6x from both sides
∴ 7x - 6x = 6x - 6x + 12
∴ x = 12
→ Substitute the value of x in the expression of UV to find it
∵ UV = 7(12) - 8 = 84 - 8
∴ UV = 76
∴ The length of the line segment UV is 76 units
Step-by-step explanation:
Given:
x = 26214.47
s = 5969.25
n = 15
t = 2.046
The confidence interval is:
CI = x ± t (s / √n)
CI = 26214.47 ± 2.046 (5969.25 / √15)
CI = (23061.06, 29367.88)