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4 years ago

10

marcy has 567 earmuffs in stock if she can put 18 earmuffs on each shelf about how many shevles does she need for all the earmuf

fs

2 answers:

Gelneren [198K]4 years ago

6 0

567/18 = 31.5 shelves
i would round to 32 because you can't have half a shelf.

Andrei [34K]4 years ago

3 0

To get our answer we divide 567 by 18
567 ÷ 18 = 31
your answer is 31

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Un deposito de agua tiene forma de prisma rectangular con los lados de la base de 25 y 20 metros. Calcula la altura que pueda co

serious [3.7K]

Answer:

La altura del depósito para que pueda contener 1000 metros cúbicos de agua es 2 m.

Step-by-step explanation:

Para calcular el volumen de un prisma rectangular, es necesario multiplicar sus 3 dimensiones: longitud*ancho*altura. El volumen se expresa en unidades cúbicas.

En este caso, se conoce la longitud y el ancho, cuyos valores son 25 y 20 metros. A su vez, se sabe que el depósito de agua debe contener 1000 m³. Entonces, siendo:

Volumen= longitud*ancho*altura

Y reemplazando los valores se obtiene:

1000 m³= 25 m* 20 m* altura

Resolviendo:

1000 m³= 500 m²* altura

$altura=\frac{1000 m^{3} }{500 m^{2} }$

altura= 2 m

<u><em>La altura del depósito para que pueda contener 1000 metros cúbicos de agua es 2 m.</em></u>

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3 years ago

Proportions happen because two events or scenarios are ___

Anni [7]

<span>Proportions happen because two events or scenarios are related or associated with one another </span>

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3 years ago

What types of solutions does 6x^2 - 20x + 1 have?

elena55 [62]

Answer:

2 real solutions

Step-by-step explanation:

We can use the determinant, which says that for a quadratic of the form ax² + bx + c, we can determine what kind of solutions it has by looking at the determinant of the form:

b² - 4ac

If b² - 4ac > 0, then there are 2 real solutions. If b² - 4ac = 0, then there is 1 real solution. If b² - 4ac < 0, then there are 2 imaginary solutions.

Here, a = 6, b = -20, and c = 1. So, plug these into the determinant formula:

b² - 4ac

(-20)² - 4 * 6 * 1 = 400 - 24 = 376

Since 376 is clearly greater than 0, we know this quadratic has 2 real solutions.

<em>~ an aesthetics lover</em>

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3 years ago

4x<br>f(x)=<br>x -3 togetherness

frozen [14]

Answer:

f(x)=2(\dfrac{2}{3})^x.

Step-by-step explanation:

f(x)=1/2(2)xf(x)=3/4(-1/5)xf(x)=(7/2)xf(x)=2(2/3)x

3 0

4 years ago

Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z

dexar [7]

Answer:

The value of the constant C is 0.01 .

Step-by-step explanation:

Given:

Suppose X, Y, and Z are random variables with the joint density function,

$f(x,y,z) = \left \{ {{Ce^{-(0.5x + 0.2y + 0.1z)}; x,y,z\geq0 } \atop {0}; Otherwise} \right.$

The value of constant C can be obtained as:

$\int_x( {\int_y( {\int_z {f(x,y,z)} \, dz }) \, dy }) \, dx = 1$

$\int\limits^\infty_0 ({\int\limits^\infty_0 ({\int\limits^\infty_0 {Ce^{-(0.5x + 0.2y + 0.1z)} } \, dz }) \, dy } )\, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y }(\int\limits^\infty_0 {e^{-0.1z} } \, dz }) \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0{e^{-0.2y}([\frac{-e^{-0.1z} }{0.1} ]\limits^\infty__0 }) \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}([\frac{-e^{-0.1(\infty)} }{0.1}+\frac{e^{-0.1(0)} }{0.1} ]) } \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}[0+\frac{1}{0.1}] } \, dy }) \, dx =1$

$10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2y} }{0.2}]^\infty__0 }) \, dx = 1$

$10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2(\infty)} }{0.2}+\frac{e^{-0.2(0)} }{0.2}] } \, dx = 1$

$10C\int\limits^\infty_0 {e^{-0.5x}[0+\frac{1}{0.2}] } \, dx = 1$

$50C([\frac{-e^{-0.5x} }{0.5}]^\infty__0}) = 1$

$50C[\frac{-e^{-0.5(\infty)} }{0.5} + \frac{-0.5(0)}{0.5}] =1$

$50C[0+\frac{1}{0.5} ] =1$

$100C = 1$ ⇒ $C = \frac{1}{100}$

C = 0.01

3 0

3 years ago