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ArbitrLikvidat [17]
3 years ago
8

Write the equation of the line that passes through the point (7,-2) and has a slope of

Mathematics
2 answers:
konstantin123 [22]3 years ago
6 0
I only know how to do a, so i hope i can help a little bit.
y=mx+b
-2=-3(7)+b
-2=-21+b
b=19
so your equation is y=-3x+19
i hope this helps!!
yarga [219]3 years ago
5 0

Answer:

Step-by-step explanation:

a) The equation of a straight line can be represented in the slope intercept form as

y = mx + c

Where

m = slope = (change in the value of y in the y axis) / (change in the value of x in the x axis)

The slope of the equation is given as - 3

The line passes through the point (7,-2)

To determine the intercept, we would substitute m = - 3, x = 7 and y = -2 into y = mx + c. It becomes

- 2 = - 3 × 7 + c = - 21 + c

c = - 2 + 21 = 19

The equation becomes

y = -3x + 19

b) the standard form is expressed as

Ax + by = C

We would substitute x = 7, y = - 2 and m = - 3 into the point slope equation, y - - 2 = - 3(x - 7)

y + 2 = - 3x + 21

3x + y = 21 - 2

3x + y = 19

The standard form is 3x + y = 19

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Gary is studying the prevalence of regional dialects. He surveyed 351 people in a region and asked what words they used for cert
chubhunter [2.5K]

Answer:

Confidence interval = ( 0.7991, 0.8647 )

Step-by-step explanation:

Sample size = n = 351

number of successes = X = 292

Sample proportion = P = \frac{X}{n}

                                     =  \frac{292}{351}

                                     = 0.831908831

confidence interval = 90%

Critical Z value  = 1.6449   [by using excel]

Confidence interval = P ± Z \sqrt{P\frac{(1-P)}{n}}

Where P = Sample proportion

           Z = critical value

           n = sample size

Confidence interval =  0.831908831 ± 1.6449 \sqrt{0.831908831\frac{(1-0.831908831)}{351}}

                                = 0.831908831 ± 1.6449 × 0.0200

                                = 0.831908831 ± 0.032898

 Lower limit             = 0.831908831 - 0.032898 = 0.7991

Upper limit               = 0.831908831 + 0.032898 = 0.8647

Confidence interval = ( 0.7991, 0.8647 )

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3 years ago
If the length of each side of a cube is doubled, is the surface area doubled? Use an example to support your answer
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If a = 6l^2 is the total area of the surface of a cube with sides l length and A = 6 (2l)^2 is that area with 2l sides, then we take the ratio A/a = 6 (2l)^2/(6 l^2) = (2l)^2/l^2 = 4l^2/l^2 = 4. So that A = 4a. And that explicitly shows that the area A with 2l for sides is 4 X a, where a is the area when l is the side length. 

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4 years ago
Show how to make a ten to solve 13-7
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4 years ago
which equation represents an exponential function that passes through the point (2, 80)? f(x) = 4(x)5 f(x) = 5(x)4 f(x) = 4(5)x
pav-90 [236]

we know that

if the exponential function passes through the given point, then the point must satisfy the equation of the exponential function

we proceed to verify each case  if the point (2,80) satisfied the exponential function

<u>case A</u>  f(x)=4(x^{5})

For x=2 calculate the value of y in the equation and then compare with the y-coordinate of the point

so

f(2)=4(2^{5})=128

128\neq 80

therefore

the exponential function  f(x)=4(x^{5}) not passes through the point (2,80)

<u>case B</u>  f(x)=5(x^{4})

For x=2 calculate the value of y in the equation and then compare with the y-coordinate of the point

so

f(2)=5(2^{4})=80

80=80

therefore

the exponential function f(x)=5(x^{4}) passes through the point (2,80)

<u>case C</u>  f(x)=4(5^{x})

For x=2 calculate the value of y in the equation and then compare with the y-coordinate of the point

so

f(2)=4(5^{2})=100

100\neq 80

therefore

the exponential function f(x)=4(5^{x}) not passes through the point (2,80)

<u>case D</u>  f(x)=5(4^{x})

For x=2 calculate the value of y in the equation and then compare with the y-coordinate of the point

so

f(2)=5(4^{2})=80

80=80

therefore

the exponential function f(x)=5(4^{x}) passes through the point (2,80)

therefore

<u>the answer is</u>

f(x)=5(x^{4})

f(x)=5(4^{x})

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Answer:Hmmm I think angry

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