Answer:
n = 4.25 x 10⁴ .
Explanation:
EMF required to be produced = 3 V .
Let n be the required no of turns .
rate of change of flux = n x B x A x f where n is no of turns of coil , B is magnetic field , A is area of coil and f is frequency of change .
B = .05 T , A = π x (.015)² = 7.065 x 10⁻⁴ m² , f = 2
emf induced = rate of change of flux
= n x .05 T x 7.065 x 10⁻⁴ m² x 2
= .7065 x 10⁴ x n
Given
.7065 x 10⁻⁴ x n = 3
n = 4.25 x 10⁴ .
Answer:
Explanation:
We need 2 different equations for this problem: first the velocity of sound equation, then the frequency of the sound equation.
The velocity of sound is found in:
v = 331.5 + .606T
We need to find that first in order to fill it into the frequency equation which is
where v is the velocity we will find the part a, f is frequency and lambda is the wavelength. Starting with the velocity of the sound:
v = 331.5 + .606(25) and
v = 331.5 + 15 and rounding correctly using the rules for sig fig when adding:
v = 347 m/s
Filling that into the frequency equation:
and
so
Answer:
0.091 sec
Explanation:
f = frequency of oscillation of the mass attached to the spring = 11 Hz
T = Time period of oscillation of the mass attached to the spring = ?
Time period and frequency of oscillation of the mass attached to the end of spring are related as
Inserting the values
T = 0.091 sec