For the following reaction, 2 SO2(g) + O:(g) 2 SO,(g) the equilibrium constant, K, is 1.32 at 627°C. What is the equilibrium con
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It will take 15 s to travel 6 cm
<h3>Further explanation</h3>Given
distance versus time graph
Required
time travel
Solution
Caterpillar motion is a straight motion with a constant speed, so that the graph between distance and time forms a diagonal line
If we look at the graph, we can determine the time taken when the distance reaches 6 cm (y axis) by drawing a line to the diagonal line and cutting the x-axis as time, and we get 15 s
Or we can also use the formula for motion at constant speed:
d = v x t
With v at point 2,5 of 2/5 m / s, so the time taken:
Answer : The amount of reactant left in excess is 13.1075 grams.
Explanation : Given,
Mass of = 26.5 g
Mass of = 10 g
Molar mass of = 53.5 g/mole
Molar mass of = 40 g/mole
First we have to calculate the moles of and
.
Now we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,
From the balanced reaction we conclude that
As, 1 mole of react with 1 mole of
So, 0.25 moles of react with 0.25 moles of
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and
is a limiting reagent and it limits the formation of product.
Moles of remaining excess reactant = 0.495 - 0.25 = 0.245 moles
Now we have to calculate the mass of .
Therefore, the amount of reactant left in excess is 13.1075 grams.
<u>Answer:</u> The mass of plastic sheet is
<u>Explanation:</u>
The plastic sheet is in the form of cuboid. To calculate the volume of cuboid, we use the equation:
where,
V = volume of cuboid
l = length of cuboid = 10.0 m = 1000 cm (Conversion factor: 1 m = 100 cm)
b = breadth of cuboid = 1.0 m = 100 cm
h = height of cuboid = 1 cm
Putting values in above equation, we get:
To calculate mass of a substance, we use the equation:
We are given:
Density of plastic sheet =
Volume of plastic sheet =
Putting values in equation 1, we get:
Hence, the mass of plastic sheet is