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mr Goodwill [35]
3 years ago
13

13.4 x 0.05 x 1.8 =?

Mathematics
1 answer:
o-na [289]3 years ago
5 0

Answer:

1.206

Step-by-step explanation:

13.4 × 0.05 × 1.8

= 67/5 × 5/100 × 9/5

= 603/500

= 1.206

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(r + 14x + 55x + 48) \(x + 6)
balu736 [363]

Answer:

r + 69x + 48 / x + 6

Step-by-step explanation:

3 0
3 years ago
What is the image of (8,-6) after a reflection over the line y = x?
wlad13 [49]

Answer:

Step-by-step explanation:

Interchange x and y:  (-6, 8) is the image of (8, -6) after a reflection over y = x.

6 0
3 years ago
PLEASE HELP Find the value of x.<br> X<br> 15<br> 12
zlopas [31]

Answer: x = 9

Step-by-Step Solution:

Hypotenuse = 15 units

Base = 12 units

Altitude = x units

Using Pythagoras Theorem,

=> Hypotenuse^2 = Base^2 + Altitude^2

(15)^2 = (12)^2 + x^2

225 = 144 + x^2

225 - 144 = x^2

81 = x^2

x^2 = 81

x = √81

=> x = 9

Therefore, Altitude = 9 units

8 0
2 years ago
Allied Corporation is trying to sell its new machines to Ajax. Allied claims that the machine will pay for itself since the time
kvasek [131]

Answer:

z(s) is in the acceptance region. We accept H₀  we did not find a significantly difference in the performance of the two machines therefore we suggest not to buy a new machine

Step-by-step explanation:

We must evaluate the differences of the means of the two machines, to do so, we will assume a CI  of 95%, and as the interest is to find out if the new machine has better performance ( machine has a bigger efficiency or the new machine produces more units per unit of time than the old one) the test will be a one tail-test (to the left).

New machine

Sample mean                  x₁ =    25

Sample variance               s₁  = 27

Sample size                       n₁  = 45

Old machine

Sample mean                    x₂ =  23  

Sample variance               s₂  = 7,56

Sample size                       n₂  = 36

Test Hypothesis:

Null hypothesis                         H₀             x₂  -  x₁  = d = 0

Alternative hypothesis             Hₐ            x₂  -  x₁  <  0

CI = 90 %  ⇒  α =  10 %     α = 0,1      z(c) = - 1,28

To calculate z(s)

z(s)  =  ( x₂  -  x₁ ) / √s₁² / n₁  +  s₂² / n₂

s₁  = 27     ⇒    s₁²  =  729

n₁  = 45    ⇒   s₁² / n₁    = 16,2

s₂  = 7,56   ⇒    s₂²  = 57,15

n₂  = 36     ⇒    s₂² / n₂  =  1,5876

√s₁² / n₁  +  s₂² / n₂  =  √ 16,2  + 1.5876    = 4,2175

z(s) = (23 - 25 )/4,2175

z(s)  =  - 0,4742

Comparing z(s) and  z(c)

|z(s)| < | z(c)|  

z(s) is in the acceptance region. We accept H₀  we did not find a significantly difference in the performance of the two machines therefore we suggest not to buy a new machine

The very hight dispersion of values s₁ = 27 is evidence of frecuent values quite far from the mean

3 0
3 years ago
Please hurry in need for help!!
d1i1m1o1n [39]

5 × x = 1/4        x = 1/4 ÷ 5        x = 1/20

7 0
3 years ago
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