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Kruka [31]
3 years ago
13

In which situation does the law of conservation of momentum apply?

Physics
1 answer:
zvonat [6]3 years ago
7 0

As per Newton's II law we know that

F = \frac{dP}{dt}

rate of change in momentum is Net outside force on the object

now here we will have if net outside force will be zero

then we can say

F = 0 = \frac{dP}{dt}

so from above equation we can say

dP = 0

and hence we have

P = constant

so the correct answer will be

<em>3.) in the absence of outside forces</em>

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How can you use the graph of velocity versus time to estimate the acceleration of the ball?
kenny6666 [7]

Answer: acceleration = slope  graph velocity vs time

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7 0
3 years ago
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A positive point charge Q is fixed on a very large horizontal frictionless tabletop. A second positive point charge q is release
Scilla [17]

Answer:

(A) As it moves farther and farther from Q, its speed will keep increasing.

Explanation:

When a positive charge Q is fixed on a horizontal frictionless tabletop and a second charge q is released near to it then according to the Coulombs law the force acting on it decreases with the square of the distance between them.

Mathematically:

F=\frac{1}{4\pi.\epsilon_0} \times \frac{Q.q}{r^2}

where:

r = distance between the charges

\epsilon_0= permittivity of free space

By the Newtons' second law of motion if the we know that the acceleration is directly proportional to the force applied. So as  the distance between the charges increases the its acceleration also decreases therefore now the charge feels less acceleration but still continues to accelerate with a fading magnitude.

7 0
3 years ago
A circuit has a voltage of 10 V and a current of 5 A. What must the resistance be?
azamat

Answer:

R=V/I

R= 2

Explanation:

R = 10V/5A

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3 0
3 years ago
g Incandescent bulbs generate visible light by heating up a thin metal filament to a very high temperature so that the thermal r
Naddika [18.5K]

Answer:

2577 K

Explanation:

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So, T = ⁴√(P/σεA)

Since P = 60 W, we substitute the vales of the variables into T. So,

T = ⁴√(P/σεA)

= ⁴√(60 W/(5.6704 × 10⁻⁸ W/m²K⁴ × 0.8 × 30 × 10⁻⁶ m²)

= ⁴√(60 W/(136.0896 × 10⁻¹⁴ W/K⁴)

= ⁴√(60 W/(13608.96 × 10⁻¹⁶ W/K⁴)

= ⁴√(0.00441 × 10¹⁶K⁴)

= 0.2577 × 10⁴ K

= 2577 K

6 0
3 years ago
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skad [1K]

\frac{100}{0.214+-0.006} = 454.55 g/cm3

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3 years ago
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