Chapter name please then I can answer
Answer:
The horizontal distance the pumpkin will travel after it slips from the eagle is 17.02 m
Explanation:
Given;
height above the ground, h = 16.4 m
speed of the eagle, v = 9.3 m/s
The time it will take the pumpkin to fall at the given height is calculated as;
The horizontal distance traveled at this time is given by;
x = vt
x = (9.3)(1.83)
x = 17.02 m
Therefore, the horizontal distance the pumpkin will travel after it slips from the eagle is 17.02 m
The magnification of the ornament is 0.25
To calculate the magnification of the ornament, first, we need to find the image distance.
Formula:
- 1/f = u⁻¹+v⁻¹.................... Equation 1
Where:
- f = Focal length of the ornament
- u = image distance
- v = object distance.
make u the subject of the equation
- u = fv/(f+v)................ Equation 2
From the question,
Given:
Substitute these values into equation 2
- u = (12×4)/(12+4)
- u = 48/16
- u = 3 cm.
Finally, to get the magnification of the ornament, we use the formula below.
- M = u/v.................. Equation 3
Where
- M = magnification of the ornament.
Substitute these values above into equation 3
Hence, The magnification of the ornament is 0.25
Answer:
The speed is
Explanation:
From the question w are told that
The angle made is
The distance above the surface of the water is
The value of
The maximum height attained by the fish is mathematically evaluate as
Making v which is the speed of the fish the subject of the formula
substituting values