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Helga [31]
3 years ago
8

Dave drove 55 mph for part of the trip and 60mph for the rest. The 245 mile trip took him 4 hours 12 minutes. How long did the 2

nd part of the trip take? How far did he drive during the 2nd part of his trip?
Mathematics
1 answer:
Lady_Fox [76]3 years ago
6 0

Answer:

<u>Dave drove 168 miles during the 2nd part of the trip</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Speed of Dave for part of the trip = 55 mph

Speed of Dave the rest of the trip = 60 mph

Total time of the round trip = 4 hours 12 minutes

Total distance of the trip = 245 miles

2. How far did Dave drive during the 2nd part of his trip?

Let's recall that the formula of speed is:

Speed = Distance/Time, therefore Distance = Speed * Time

x = Time of part of the trip

4 hours 12 minutes - x = Time of the rest of the trip

4.2 hours - x = Time of the rest of the trip

Now, we can write solve for x, this way:

55 * x + 60 (4.2 - x) = 245

55x + 252 - 60x = 245

-5x = 245 - 252

-5x = -7

x = -7/-5 = 7/5 = 1.4 ⇒ 4.2 - x = 2.8

1st part of the trip = 55 * 1.4 = 77 miles

2nd part of the trip = 2.8 * 60 = 168 miles

<u>Dave drove 168 miles during the 2nd part of the trip and 77 miles during the 1st part</u>

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\large\bf{\underline{Answer:}}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{ = 3000 \:ft^2}

__________________________________________

\large\bf{\underline{Given:}}

  • A 3 dimensional figure with 5 sides
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\large\bf{\underline{To\: find:}}

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\large\bf{\underline{Therefore:}}

\bf{area \:of\: figure}

‎ㅤ{\bf = area \:of \:3\: rectangles + 2 \: triangles}

\large\bf{\underline{Formulas:}}

\boxed{\bf\pink{area\:of\: triangle= \frac{1}{2}\times base\times height}}

\boxed{\bf\pink{area\:of\: rectangle=length\times breadth}}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{= 3\times (28 \times 25 )+ 2(\frac{1}{2} \times 30 \times 20)}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{= 3 \times 800 + 2 \times 300}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{=2400+ 600}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{= 3000}

__________________________________________

\large\bf{\underline{Hence,}}

❒ Area of given figure

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\huge\mathfrak{= 3000\: ft^2}

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