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zimovet [89]
3 years ago
10

In unguided medium (free space), the electromagnetic (EM) signal wave spreads as it leaves the transmit antenna. Since the power

of the EM signal resides in the surface area of the wave front, signal power is described as signal power density (i.e., watts per area).
True

False

The spreading of an electromagnetic (EM) signal in an unguided medium such as air, weakens the EM signal therefore causing signal attenuation.

True

False
Engineering
1 answer:
natka813 [3]3 years ago
4 0
The real answer - for 1- true
you have to pay attention in class to actually learn this subject if you want to work in this workforce


second - false
there is no way that the Elecrtomagnetic signal can just cause awful signal attenuation.
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An aluminum alloy tube with an outside diameter of 3.50 in. and a wall thickness of 0.30 in. is used as a 14 ft long column. Ass
slega [8]

Answer:

slenderness ratio = 147.8

buckling load = 13.62 kips

Explanation:

Given data:

outside diameter is 3.50 inc

wall thickness 0.30 inc

length of column is 14 ft

E = 10,000 ksi

moment of inertia = \frac{\pi}{64 (D_O^2 -D_i^2)}

I = \frac{\pi}{64}(3.5^2 -2.9^2) = 3.894 in^4

Area = \frac{\pi}{4} (3.5^2 -2.9^2) = 3.015 in^2

radius = \sqrt{\frac{I}{A}}

r = \sqrt{\frac{3.894}{3.015}

r = 1.136 in

slenderness ratio = \frac{L}{r}

                              = \frac{14 *12}{1.136} = 147.8

buckling load = P_cr = \frac{\pi^2 EI}}{l^2}

P_{cr} = \frac{\pi^2 *10,000*3.844}{( 14\times 12)^2}

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3 0
3 years ago
A disk‑shaped part is to be cast out of aluminum. The diameter of the disk = 401 mm and its thickness = 25 mm. If the mold const
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Answer:    

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Explanation:

3 0
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Answer:

35psig

Explanation:

Pressure is a force that acts on a surface area. The psig measure the pressure pounds per square inch gauge. It measure the difference in pressure between supply tank and outside air. This pressure is relative to atmospheric pressure. When charging an R-410A system, the vapor pressure should be at least 35 psig before switching to liquid charging.

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Using six bits, Show the binary counting sequence from 000000 to 111111
fenix001 [56]

Answer:

Explanation:

The least significant unit bits switch from 0 → 1 or 1 → 0 with each count.

The next bit(two-position) which is the second bit usually be at 0s for two counts and at  1s at two counts. The third bit (four positions) usually be at 0s for four counts and then at 1 for four counts. etc. The fourth bit (eight positions) usually be at 0s for eight counts and then at 1 for eight counts and so on. The fifth bit (sixteen positions) usually be at 0s for sixteen counts and then at 1 for sixteen counts and so on. The sixth bit (thirty-two positions) usually be at 0s for thirty-two counts and then at 1 for thirty-two counts and so on in the sequence of six-bit binary counting.

From the document attached below, we can see a document file showing the binary counts sequences from 000000 to 111111.

Download docx
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