Answer:
![\sqrt[3]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3%7D)
Step-by-step explanation:
Our expression is: ![\frac{1}{3} \sqrt[3]{81}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D%20%5Csqrt%5B3%5D%7B81%7D)
.
Let's focus on the cube root of 81 first. What's the prime factorisation of 81? It's simply: 3 * 3 * 3 * 3, or 
. Put this in for 81:
![\sqrt[3]{81} =\sqrt[3]{3^3*3}=\sqrt[3]{3^3} *\sqrt[3]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B81%7D%20%3D%5Csqrt%5B3%5D%7B3%5E3%2A3%7D%3D%5Csqrt%5B3%5D%7B3%5E3%7D%20%2A%5Csqrt%5B3%5D%7B3%7D)
We know that the cube root of 3 cubed will cancel out to become 3, but the cube root of 3 cannot be further simplified, so we keep that. Our outcome is then:
![\sqrt[3]{3^3} *\sqrt[3]{3}=3\sqrt[3]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3%5E3%7D%20%2A%5Csqrt%5B3%5D%7B3%7D%3D3%5Csqrt%5B3%5D%7B3%7D)
Now, let's multiply this by 1/3, as shown in the original problem:
![\frac{1}{3}* 3\sqrt[3]{3}=\sqrt[3]{3}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D%2A%203%5Csqrt%5B3%5D%7B3%7D%3D%5Csqrt%5B3%5D%7B3%7D)
Thus, the answer is .
<em>~ an aesthetics lover</em>
Answer:
E
E is the only one that ends with 70 and is also all multiples of 6.
Answer: B
how close their measurements are to each other
Step-by-step explanation:
The students in a science class did not know the length of the board before taking turns to measure the length of a certain board.
The characteristic of their measurements that best indicates
their accuracy will be how close their measurements are to each other.
If the actual length is known before the carry out the measurements, there average value will be neccessarily to determine their accuracy.
Therefore, option B is the best option.
The surface area of a rectangular prism is given by
... S = 2(LW +H(L+W))
For your dimensions, the surface area is
... S = 2(3·1 + 2(3+1)) = 2(3 + 8) = 22 . . . ft²
Answer:
A and C
Step-by-step explanation:
Nothing much, just add 2 1/2 to 3 2/3 and subtract 2 1/2 from 3 2/3
