Answer:
6.6 atm
Explanation:
Using the general gas law
P₁V₁/T₁ = P₂V₂/T₂
Let P₂ be the new pressure
So, P₂ = P₁V₁T₂/V₂T₁
Since V₂ = 2V₁ , P₁ = 12 atm and T₁ = 273 + t where t = temperature in Celsius
T₂ = 273 + 2t (since its Celsius temperature doubles).
Substituting these values into the equation for P₂, we have
P₂ = P₁V₁(273 + 2t)/2V₁(273 + t)
P₂ = 12(273 + 2t)/[2(273 + t)]
P₂ = 6(273 + 2t)/(273 + t)]
assume t = 30 °C on a comfortable spring day
P₂ = 6(273 + 2(30))/(273 + 30)]
P₂ = 6(273 + 60))/(273 + 30)]
P₂ = 6(333))/(303)]
P₂ = 6.6 atm
Answer:
Explanation:
Initial is all kinetic energy
final is all potential energy (spring)
½kx² = ½mv²
x = √(mv²/k) = √(1.3(2.8²) / 800) = 0.01274 m or about 1.3 cm
L = L₀ - x = 0.439 - 0.013 = 0.426 m
F = kx = 800(0.01274) = 10.192 or about 10.2 N
Answer:
f = 409 Hz
Explanation:
We have,
Length of the open organ pipe, l = 0.29 m
Frequency of vibration of second overtone,
It is required to find the fundamental frequency of the pipe. For the open organ pipe, the frequency of second overtone is given by :
v is speed of sound
Let f is the fundamental frequency. It is given by :
The relation between f and f₂ can be written as :
So, the fundamental frequency of the pipe is 409 Hz.
Answer:
3.96 meters / sec
Explanation:
The skaters Kinetic Energy is converted to Potential Energy ( ignoring friction)
KE = PE
1/2 * 55 * v^2 = 55 * 9.81 * .8
solve for v = 3.96 m/s
Answer:
Higher launch angles have higher maximum height
Since steeper launch angles have a larger vertical velocity component, increasing the launch angle increases the maximum height.