Let the vector position of the object in the (x-y) plane be

The applied force is

By definition, the applied torque is

Answer:
In this question a lot of information's are provided. Among the information's provided one information and that is the time of 4 seconds is not required for calculating the answer. Only the other information's are required.
Mass of the block that is sliding = 5.00 kg
Distance for which the block slides = 10 meters/second
Then we already know that
Momentum = Mass * Distance travelled
= (5 * 10) Kg m/s
= 50 kg m/s
So the magnitude of the blocks momentum is 50 kg m/s. The correct option among all the given options is option "b".
Answer:
The answer is
<h2>84.9 kPa</h2>
Explanation:
Using Boyle's law to find the final pressure
That's

where
P1 is the initial pressure
P2 is the final pressure
V1 is the initial volume
V2 is the final volume
Since we are finding the final pressure

From the question
P1 = 115 kPa
V1 = 480 mL
V2 = 650 ml
So we have

We have the final answer as
<h3>84.9 kPa</h3>
Hope this helps you