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swat32
4 years ago
12

A car is traveling in a circular curve on a horizontal road at constant speed. Name the force that is responsible for causing it

s circular motion? a the gravity force b the normal force from the road c the friction force from the road d the tension force
Physics
1 answer:
I am Lyosha [343]4 years ago
4 0
The correct answer is
<span>c the friction force from the road 

In fact, the friction force between the road and the tires prevents the car from "sliding away" in a straight line and keeps it in circular motion, acting as centripetal force.</span>
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Find the height of the coconut from the ground at the moment the arrow hit it.
Wewaii [24]

Answer:

v = u + at \\ 0 = 45 \sin(20)  -  9.81 \times t  \\ t = 1.56s

7 0
2 years ago
As blood passes through the capillary bed in an organ, the capillaries join to form venules (small veins). If the blood speed in
Semenov [28]

Answer:

A_2 = 2.5\ cm^2

Explanation:

given,

velocity factor = 4

Cross-sectional area of venules(A₁) = 10 cm²

cross sectional area of capillaries(A_2) = ?

continuity equation = Q = AV

now,

\dfrac{A_1}{A_2} = \dfrac{V_2}{V_1}

\dfrac{10}{A_2} =4

\dfrac{10}{4} =A_2

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4 0
3 years ago
Sean climbs a tower that is 71.3 m high to make a jump with a parachute. The mass of Sean plus the parachute is 81.4 kg. If U =
myrzilka [38]

Answer:

U = 56877.4 J

Explanation:

The potential energy of a body is that which it possesses because it is located at a certain height above the surface of the earth and can be calculated using the following formula:

U = mgh Formula (1)

Where:

U is the potential energy in Joules (J)

m is the mass of the body in kilograms (kg)

g is the acceleration due to gravity (m/s²)

h is the height at which the body is found from the surface of the earth in meters (m)

Data

m= 81.4 kg

g= 9.8 m/s²

h = 71.3 m

Potential energy of Sean and the parachute at the top of the tower

We replace data in the formula (1)

U = m*g*h

U = (81.4 kg)*(9.8 m/s²)*(71.3 m)

U = 56877.4 N*m

U = 56877.4 J

3 0
4 years ago
It may seem strange that the selected velocity does not depend on either the mass or the charge of the particle. (For example, w
Charra [1.4K]

Answer:

b) q large and m small

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q is large and m is small

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F = Eq

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F = Bqv

F = \frac{mv^{2} }{r}

Bqv = \frac{mv^{2} }{r}

or Eq = \frac{mv^{2} }{r}

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6 0
3 years ago
The rainbow is a result of a. Diffraction of the light.
suter [353]

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Choice C

5 0
3 years ago
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