Question

While rearranging a dorm room, a student does 310 J of work in moving a desk 2.9 m. What was the magnitude of the applied horizontal force?

Answer 1

Answer:

The horizontal force is 106.89 N.

Explanation:

Given that,

Work done = 310 J

Distance = 2.9 m

We need to calculate the horizontal force

Using formula of work done

$W= Fd\cos\theta$

Where, $\theta=0^{\circ}$

$W=F\cdot d$

Put the value into the formula

$310=F\cdot 2.9$

$F=\dfrac{310}{2.9}$

$F=106.89\ N$

Hence, The horizontal force is 106.89 N.