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3 years ago

6

When using two-wire cable to feed a 240-V appliance that does not require a neutral wire, you should A. mark both ends of the wh

ite wire green. B. use the cable as is. C. use only the black wire. D. mark both ends and any exposed area of the white wire black.

1 answer:

DENIUS [597]3 years ago

3 0

A, you always want to mark wires with a color that is noticeable

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3 years ago

The maximum allowable resistance for an underwater cable is one hundredth of an ohm per

Studentka2010 [4]

Answer:

A = 1.54 x 10⁻⁵ m² = 15.4 mm²

Explanation:

The resistance of a wire can be given by the following formula:

$R = \frac{\rho L}{A}\\\\A = \frac{\rho L}{R} = \frac{\rho}{\frac{R}{L} }$

where,

A = smallest cross-sectional area = ?

ρ = resistivity of copper = 1.54 x 10⁻⁸ Ωm

$\frac{R}{L}$ = resistance per unit length of wire = 0.001 Ω/m

Therefore,

$A = \frac{1.54\ x\ 10^{-8}\ \Omega m}{0.001\ \Omega/m}$

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3 years ago

A block oscillating on a spring has period T = 2.8 s . (Note: You do not know values for either m or k. Do not assume any partic

olasank [31]

Answer:

Part a)

T = 3.96 s

Part b)

T = 1.98 s

Part c)

T = 2.8 s

Explanation:

As we know that time period of spring block system is given as

$T = 2\pi\sqrt{\frac{m}{k}}$

T = 2.8 s

Part a)

If the mass of the block attached is doubled

then we will have

$T' = 2\pi\sqrt{\frac{2m}{k}}$

$T' = \sqrt2 T$

$T' = 3.96 s$

Part b)

If the spring constant is doubled

then we have

$T' = 2\pi\sqrt{\frac{m}{2k}}$

$T' = \frac{T}{\sqrt2}$

$T' = 1.98 s$

Part c)

If the amplitude is halved but mass and spring constant will remain the same

so here we know that time period does not depends on Amplitude

so we will have

$T = 2\pi\sqrt{\frac{m}{k}}$

T = 2.8 s

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3 years ago