3 years ago

What is the slope of the line shown below? (2.5 (3,-5)

Mathematics

1 answer:

frozen [14]3 years ago

6 0

Answer:

m = -10

Step-by-step explanation:

x2 - x1

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3y-3.5/3y+6=17/25.5. find the value of y. give the scale factor of the polygon

Mekhanik [1.2K]

Hi the answer to your question is

((3y - 3.5) / (3y + 6)) * 25.5 = (17 / 25.5) * 25.5

((3y - 3.5) / (3y + 6)) * 25.5 = 17 (76.5y - 89.25) / (3y + 6) = 17

((76.5y - 89.25) / (3y + 6)) * (3y + 6) = 17 * (3y + 6) 76.5y - 89.25 = 51y + 102 76.5y - 51y = 102 + 89.25

25.5y = 191.25

y = 191.25 / 25.5

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3 years ago

PLS HELP (LAST QUESTION)

rosijanka [135]

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Step-by-step explanation:

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3 years ago

Mackenzie spent a total of $17.50 on Saturday afternoon.She bought a movie ticket for $7.25 and snacks for $4.95.She spent the r

Helga [31]

17.50-7.25-4.95=5.30/2=2.65

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2 years ago

In 1967, New Zealander Burt Munro set the world record for an Indian motorcycle, on the Bonneville Salt Flats in Utah, with a ma

bagirrra123 [75]

Answer:49 sec

Step-by-step explanation:

Given

Maximum speed to reach is 183.58 mi/h

Length of course is 5 mi

acceleration rate is defined by 60mi/h in 4 sec

therefore acceleration(a) $=\frac{v-u}{t}$

$a=\frac{60\times 60\times 60}{4}$

$a=54\times 10^3 mi/h^2$

To reach a speed of 183.58mi/h with an acceleration of $54\times 10^3 mi/h^2$

Using equation of motion

v=u+at

$183.58=0+(54\times 10^3)t$

$t=\frac{183.58}{54\times 10^3}$

t=0.00339 hours

t=12.23 s reach maximum speed

To complete course it takes

$s=ut+\frac{1}{2}at^2$

$5=0+\frac{1}{2}\times 54\times 10^3 \times t^2$

t=0.01360 hour

or $t=48.98\approx 49 s$

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3 years ago

You deposit $ 1200 in an account. The annual interest rate is 3%. How long will it take you to earn $108 in simple interest?

alukav5142 [94]

The correct answer is 3

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3 years ago