Consider the function f(x) =c/x

Find the coordinates of the intersection of the diagonals of parallelogram HJKL with the given vertices: H(-1, 4), J(3, 3), K(3,

lakkis [162]

Answer:

(1, 1)

Step-by-step explanation:

Given vertices of the parallelogram:

H = (-1, 4)
J = (3, 3)
K = (3, -2)
L = (-1, -1)

Therefore the parallel sides are:

$\sf \overline{HJ} \parallel \overline{LK}\:\: \textsf{ and }\:\: \overline{LK} \parallel \overline{HL}$

Therefore, the diagonals of the parallelogram are:

$\sf \overline{LJ} \:\: \textsf{ and }\:\:\overline{HK}$

To find the coordinates of the intersection of the diagonals, either:

draw a diagram (see attached) and determine the point of intersection of the diagonals from the diagram, or
determine the midpoint of either diagonal (as the diagonals of a parallelogram bisect each other, i.e. divide into 2 equal parts).

Midpoint between two points

$\textsf{Midpoint}=\left(\dfrac{x_2+x_1}{2},\dfrac{y_2+y_1}{2}\right)\quad \textsf{where}\:(x_1,y_1)\:\textsf{and}\:(x_2,y_2)\:\textsf{are the endpoints}}\right)$

To find the midpoint of diagonal LJ, define the endpoints:

$(x_1,y_1)=L=(-1, -1)$
$(x_2,y_2)=J=(3,3)$

Substitute the defined endpoints into the formula and solve:

$\begin{aligned} \implies \textsf{Midpoint of LJ} & =\left(\dfrac{3-1}{2},\dfrac{3-1}{2}\right)\\ & =\left(\dfrac{2}{2},\dfrac{2}{2}\right)\\ & =\left(1,1\right) \end{aligned}$

Therefore, the coordinates off the intersection of the diagonals of parallelogram HJKL are (1, 1).

Learn more about midpoints here:

brainly.com/question/27962681

8 0

2 years ago

Read 2 more answers

dale has $25 to spend at a carnival. if the admission to the carnival is $5 and the rides cost $1.50 each, what is the greatest

Anuta_ua [19.1K]

$25-5=20
20÷ 1.50=13.333333333
Round off the answer and you get 13

5 0

4 years ago

Running at the same constant rate, 5 identical machines can produce one lot containing a certain number of toys per hour. At thi

inessss [21]

Answer:

$1.6\cdot{x}$

Step-by-step explanation:

If the speed is constant for 5 machines and produces x amount of toys we know that rate is defined as a constant per time:

Here the machines are constant and the rate is x toys per hour:

If 5 machines make x per hour:

Rate is x/1 hour

The the ratio of 8/5 is 1.6. Therefore for 8 machines the rate is 1.6 times more per hour than for5 machines. Therefore we can write an expression as:

Rate for 5 machines is x and for 8 machines is y:

$y=1.6\cdot{x}$

6 0

3 years ago

What is an interquartile range?

Wewaii [24]

Answer:

See below.

Step-by-step explanation:

The IQR is the difference between the upper quartile of a set of data and the lower quartile of the data.

It is a measure of the spread of the data.

3 0

3 years ago

Elmer purchased a used vehicle that depreciates under a straight line method. The initial value of the car is $9600 and the salv

Igoryamba

Answer:

The depreciation each year is option B. $1500.00

Step-by-step explanation:

Initial value of car = $9600

Salvage value = $600

Salvage value is the final value of product after all the depreciation have been applied on the product.

So, total depreciation on the car = $\$9600 - \$600 \Rightarrow \$9000$

Also, it is given that the depreciation occurs at a straight line method i.e. same depreciation occurs every year.

Depreciation in 6 years = $9000

Depreciation in 1 year =

$\dfrac{\$9000}{6} \Rightarrow \$1500$

Hence, option B. $1500 is the correct answer for the depreciation every year.

6 0

3 years ago