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amm1812
3 years ago
12

What is double of 16

Mathematics
2 answers:
m_a_m_a [10]3 years ago
8 0

Answer:

32

Step-by-step explanation:

16+16=32

or you can say 16*16=32

azamat3 years ago
7 0

Answer:

Double of 16 is 32.

Step-by-step explanation:

Doubling a number is multiplying that number by 2 which concludes the answer 32, because 16*2=32. Hope this works!

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1. Natoy's rectangular swimming pool has the length of 3m more than thrice its
snow_lady [41]

Answer:

Step-by-step explanation:

Given

Natoy's rectangular swimming pool has the length of 3m more than thrice its

width.

Width=w

Length =3w+3

So

Area of the rectangular swimming pool=length×width

216=(3w+3)×w

216=3w^2+3w

3w^2+3w-216=0

3(w^2+w-72)=0

W^2+w-72=0

W^2+(9-8)w-72=0

W^2+9w-8w-72=0

W(w+9)-8(w+9)=0

(W+9)(w-8)=0

Sotwo value of w are 8,-9

We take positive value for rectangular swimming so we take w=8m

Width=8m

Length=3×8+3

= 24+3

=27m

6 0
3 years ago
Find the value 'X' in this given picture
taurus [48]
Hi.
This is just messing around with exterior angles.
I say around 120 degrees, if I forgot what exterior angles were.
But <em>with quick calculation, it is probably 120 degrees</em>
5 0
4 years ago
Read 2 more answers
Ray
monitta

We are given that:

m∠AOB = m∠AOC + m∠COB

We are also given that:

m∠AOC = m∠COB + 15

m∠AOB = 155

Therefore:

155 = m∠COB + 15 + m∠COB

2 m∠COB = 140

m∠COB = 70°

and,

m∠AOC = m∠COB + 15 = 85°

 

Answers:

m∠COB = 70°

m∠AOC = 85<span>°</span>

6 0
3 years ago
Change the following numbers to decimals and round to the nearest hundredth <br> 5/9
love history [14]

Answer:

Answer: 5/9 as a decimal is 0.556.

6 0
3 years ago
Read 2 more answers
PLEASE HELP ME! I really need help y'all...
ikadub [295]

just a quick clarification, tis usually -4.9 and that's a rounded number to reflect earth's gravity on an object in motion, but -5 is close enough :)

\bf ~~~~~~\textit{initial velocity in meters} \\\\ h(t) = -4.9t^2+v_ot+h_o \quad \begin{cases} v_o=\textit{initial velocity}\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}\\ \qquad \textit{of the object}\\ h=\textit{object's height}\\ \qquad \textit{at "t" seconds} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf h(x)=-5(\stackrel{\mathbb{F~O~I~L}}{x^2-8x+16})+180\implies h(x)=-5x^2+40x-80+180 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill h(x)=-5x^2+\stackrel{\stackrel{v_o}{\downarrow }}{40} x+\stackrel{\stackrel{h_o}{\downarrow }}{\boxed{100}}~\hfill

8 0
4 years ago
Read 2 more answers
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