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Arturiano [62]
3 years ago
14

Two equal point charges QQQ are separated by a distance ddd. One of the charges is released and moves away from the other due on

ly to the electrical force between them. When the moving charge is a distance 3ddd from the other charge, what is its kinetic energy?
Physics
1 answer:
lys-0071 [83]3 years ago
4 0

Answer:

The kinetic energy K of the moving charge is K = 2kQ²/3d = 2Q²/(4πε)3d = Q²/6πεd

Explanation:

The potential energy due to two charges q₁ and q₂ at a distance d from each other is given by U = kq₁q₂/r.

Now, for the two charges q₁ = q₂ = Q separated by a distance d, the initial potential energy is U₁ = kQ²/d. The initial kinetic energy of the system K₁ = 0 since there is no motion of the charges initially. When the moving charge is at a distance of r = 3d, the potential energy of the system is U₂ = kQ²/3d and the kinetic energy is K₂.

From the law of conservation of energy, U₁ + K₁ = U₂ + K₂

So, kQ²/d + 0 = kQ²/3d + K

K₂ = kQ²/d - kQ²/3d = 2kQ²/3d

So, the kinetic energy K₂ of the moving charge is K₂ = 2kQ²/3d = 2Q²/(4πε)3d = Q²/6πεd

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Marta_Voda [28]

Answer:

Hans is more powerful

Explanation:

Power: This can be defined as the rate at which work is done or energy is used up.

The expression for power is given as,

P = E/t

P = mgh/t................. Equation 1

Where P = power, W = Work, t = time, m = mass, h = height, g = acceleration due to gravity.

Hans' power

P = mgh/t

Given: m = 100 kg, h = 2 m, g = 9.8 m/s², t = 3 s

Substitute into equation 1

P = 100(9.8)(2)/3

P = 653.33 W.

Frans' power

P' = mgh/t

Given; m = 200 kg, h = 5 m, t = 20 s.

P' = 200(5)(9.8)/20

P' = 9800/20

P' = 490 W

from the above,

since P>P'

Hence, Hans is more powerful

8 0
2 years ago
A feather, a tennis ball, and a bowling ball are dropped from a high tower on
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Answer:

In the absence of air resistance. I think no. D ) The bowling ball.

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What force is required to accelerate a 1840 kg car from 4.77 m/s to 23.5 m/s,
neonofarm [45]
A :-) for this question , we should apply
a = v - u by t
Given - u = 4.77 m/s
v = 23.5 m/s
t = 5.18 m/s
Solution -
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a = 23.5 - 4.77
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Butoxors [25]
I believe it is the first one
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Kobotan [32]

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Work Done = Energy

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