The average useful power output of robot is 0.0001 W
The time taken by robot to lift bricks is 630000000 sec
Given:
work done by robot = 5.5 j
time taken to do the work = 12.0 hours
weight of bricks = 3500 kg
length of bricks = 1.8 m
To Find:
The average useful power output of robot is
The time taken by robot to lift bricks is
Solution: Useful power output means the electric or mechanical energy made available for use, exclusive of any such energy used in the power production process.
P = W/t
P = 5.5/12*3600
P = 0.0001 W
So, average useful power output of robot is 0.0001 W
t = W/P
W = mgh So t = mgh/P
t = 3500x10x1.8/0.0001
t = 630000000 sec
So, time taken by robot to lift bricks is 630000000 sec
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Answer:
3.63 s
Explanation:
We can solve the problem by using the equivalent SUVAT equations for the angular motion.
To find the angular acceleration, we can use the following equation:
where
is the final angular speed
is the initial angular speed
is the angular distance covered
is the angular acceleration
Re-arranging the formula, we can find :
Now we want to know the time the bit takes starting from rest to reach a speed of . So, we can use the following equation:
where:
is the angular acceleration
is the final speed
is the initial speed
t is the time
Re-arranging the equation, we can find the time:
The net force acting on the car is 65 N to the left
The net force acting on an object is simply defined as the resultant force acting on the object.
From the question given, we obtained the following data:
- Force applied to the right (Fᵣ) = 250 N
- Force applied to the left (Fₗ) = 315 N
- Net force (Fₙ) =?
The net force acting on the car can be obtained as follow:
Fₙ = Fₗ – Fᵣ
Fₙ = 315 – 250
<h3>Fₙ = 65 N to the left </h3>
Therefore, the net force acting on the car is 65 N to the left
Learn more on net force: brainly.com/question/19549734