5000 grams K convert to moles

Aliun [14]

1.A (when acids react with organic molecules on your skin the reaction is highly exothermic which is why it burns you)
2.C (acids and bases can dissociate into ions or create ions)
3. B (bases tend to taste bitter an example being soap)
4.A (acids tend to taste sour an example being citric acid from lemons)
5. A (the arrhenius acid definition is that acids dissociates into H⁺ ions)
6. B (the arrhenius base definition is that bases dissociate into OH⁻ ions)
7. C (Strong acid-strong base or weak acid-strong base reactions form water and salts)
8. A (I have heard that some metals can be corroded by some bases but I don't think bases usually corrode metal)
9. A (acids have lower pH values with 7 being neutral)
10. B (bases have higher pH values with 7 being neutral)
11. A (these are some of the strong acids)
12. B (these are some of the strong bases)

I hope this helps. Let me know if anything is unclear.

6 0

3 years ago

What is the percent yield if 107.50 g NH3 reacts with excess O2 according to the

Maksim231197 [3]

Answer:

81.59%

Explanation:

4NH₃ + 5O₂ → 4NO + 6H₂O

First we convert 107.50 g of NH₃ into moles, using its molar mass:

107.50 g NH₃ ÷ 17 g/mol = 6.32 mol NH₃

Now we calculate how many moles of NO would have been formed by the complete reaction of 6.32 moles of NH₃:

6.32 mol NH₃ * $\frac{4molNO}{4molNH_3}$ = 6.32 mol NO

Then we convert 6.32 moles of NO to grams, using its molar mass:

6.32 mol NO * 30 g/mol = 189.60 g NO

Finally we calculate the percent yield:

154.70 g / 189.60 g * 100% = 81.59%

8 0

3 years ago

Why does knowing the mass of an object not help you identify what material the object is made from?

jeka57 [31]

Because mass is not always the same for objects made from the same material. Just because an object has the same mass as another doesn’t mean they are the same material.

4 0

4 years ago

Barbiturates are synthetic drugs used as sedatives and hypnotics. Barbital ( = 184.2 g/mol) is one of the simplest of these drug

DanielleElmas [232]

Answer:

118.75°C is the boiling point of a solution.

Explanation:

Mass of the solute that is barbiturates = 42.5 g

Molar mass of a solute = 184.2 g/mol

Moles of solute = $\frac{42.5 g}{184.2 g/mol}=0.2307 mol$

Mass of the solvent that acetic acid = 825 g = 0.825 kg

$molality=\frac{\text{Moles of solute}}{\text{Mass of solvent}}$

Molality of the solution (m):

$m=\frac{0.2307 mol}{0.825 kg}=0.2796 m$

Elevation in boiling point is given as:

$\Delta T_b=i\times K_b\times m$

i = 1 (organic compound)

$=1\times 3.07^oC/m\times 0.2796 m=0.8585^oC$

$\Delta T_b=T_b-T$

$T_b$ = Boiling temperature of solution.

T = boiling temperature of solvent that is acetic acid=117.9°C

$0.8585^oC=T_b-117.9^oC$

$T_b=118.75 ^oC$

118.75°C is the boiling point of a solution.

6 0

3 years ago

Instead of 6 M NaOH being added to the solution, 6 M HCl is added. How will this affect the test for the presence of ammonium io

Lera25 [3.4K]

Answer:

Ammonia gas(an alkaline gas with characteristics of choking or irritating smell) is not liberated when 6mole of HCl is added to the solution instead of 6mole of NaOH, to test for the presence of ammonium ion in the solution

Explanation:

As expected, when testing for ammonium ion in a solution (precisely ammonium salt solution), Sodium Hydroxide (NaOH) is required as the test reagent.

When NaOH is added to the solution, A gas with characteristics of choking or irritating smell is liberated.

This gas turn red litmus paper blue.

This liberated gas is an alkaline gas, which is confirmed as an ammonia gas(NH3).

If HCl is added instead of NaOH, the ammonia gas will not be liberated, which indicates that the test reagent used is wrong.

3 0

3 years ago