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Lelechka [254]
3 years ago
11

g Larry , Moe, and Curly are pushing on a 25 kg crate. The crate is sitting on a horizontal floor, and the coefficient of kineti

c friction between the floor and the crate is 0.25. Larry pushes to the right with a force of 400 N. Moe pushes to the left with a force of 250 N. Curly pushes straight downward on the crate with a force of 150 N. What is the acceleration of the crate
Physics
1 answer:
kobusy [5.1K]3 years ago
7 0

Answer:2.05 m/s^2

Explanation:

Given

Mass of crate is m=25\ kg

coefficient of kinetic friction \mu _k=0.25

Larry Pushes with a force of F_L=400\ N to the right

Moe pushes with a force of F_m=250\ N to the left

Curly Pushes downward with a force of F_c=150\ N

Net Normal reaction on the ground is

N=mg+F_c

N=25\times 9.8+150=395\ N

Friction force is given by f=\mu _k\cdot N

f=0.25\times 395

f=98.75\ N

Friction Force always opposes the motion

Net Horizontal force on the  box is

F_{net}=400-250-98.75

F_{net}=51.25\ N

acceleration is given by

a=\frac{F_{net}}{m}

a=\frac{51.25}{25}

a=2.05\ m/s^2

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Hello!

Recall the period of an orbit is how long it takes the satellite to make a complete orbit around the earth. Essentially, this is the same as 'time' in the distance = speed * time equation. For an orbit, we can define these quantities:

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