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Aleks04 [339]
3 years ago
5

Will mark brainliest if correct!!!!!!!!!!!!!!!!!!!!!!!!!!!

Physics
1 answer:
goblinko [34]3 years ago
5 0

Answer:A

Explanation:

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The graph above shows the position x as a function of time for the center of mass of a system of particles of total mass 6. 0 kg
kumpel [21]

The resulting change in momentum of the system will be +18.6 Ns. The momentum is conserved.

<h3>What is the law of conservation of momentum?</h3>

According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

The given data in the problem is;

m is the mass =6.0 kg

t is the time interval=2 second

From Newton's second law;

\rm \triangle P =m \triangle V \\\\ \triangle P= m(\frac{\triangle x}{\triangle t} )\\\\

From the graph;

\rm \triangle t = 2sec\\\\ \triangle x = (12-8) m

The change in the momentum is;

\rm \triangle P = m\tr(\frac{v-u}{t}) \\\\ \triangle P =9.3 \times \frac{12-8}{2} \\\\ \triangle P= +18.6 \  N.s

Hence, the resulting change in momentum of the system will be +18.6 Ns.

To learn more about the law of conservation of momentum, refer;

brainly.com/question/1113396

#SPJ1

6 0
2 years ago
parallel-plate capacitor is made of two square plates 25 cm on a side and 1.0 mmapart. The capacitor is connected to a 50.0-V ba
noname [10]

Answer:

6.9 x 10^-7 J  

3.5 x 10^-7 J

Explanation:

<u>Identify the unknown:  </u>

The energies stored in the capacitor before and after the plates are pulled farther apart  

<u>List the Knowns: </u>

Voltage of the battery: V = 50 V

Area of the plates: A = 0.25 x 0.25 = 0.0625 m^2

Original distance between the plates: d = 1 mm = 10^-3 m

New distance between the plates: d = 2 mm = 2 x 10^-3 m

Permittivity of free space: ∈o = 8.85 x 10^-12 C^2/Nm^2-

<u>Set Up the Problem:   </u>

Capacitance of a parallel-plate capacitor:  

C=∈o*A/d

Energy stored in a capacitor:  

U_c=(1/2)*V^2*C

<u>Solve the Problem:   </u>

<u>Before the plates are pulled farther apart:  </u>

C = 8.85 x 10^-12 x 0.0625/10^-3 = 5•53 x 10^-10 F  

U_c = (1/2) x (50)^2 x 5.53 x 10^-10= 6.9 x 10^-7 J  

<u>After the plates are pulled farther apart:  </u>

C = 8.85 x 10^-12 x 0.0625/2*10^-3 = 2•77 x 10^-10 F  

U_c = (1/2) x (50)^2 x 2•77 x 10^-10 = 3.5 x 10^-7 J  

The energy decrease because the capacitance decrease, so the stored charge decrease and transferred to the battery  

3 0
3 years ago
When light travels through a small hole, it appears to be an observer that the light spreads out, blurring the outline of the ho
3241004551 [841]

Answer:

support lights as a wave

Explanation:

In the model of light as a particle, the experimenter would expect to see one small hole of light emerging on the wall. However, as the light spreads out, it behaves much like a wave that diffracts when going through a small hole.

7 0
3 years ago
Types of cell combination? in electricity​
Grace [21]

Answer:

Series and Parallel

7 0
3 years ago
What is the magnetic field at the center of a circular loop
Elan Coil [88]

Answer:

The magnetic field at the center of a circular loop is 3.14\times10^{-5}\ T.

Explanation:

Given that,

Radius = 4.0 cm

Current = 2.0 A

We need to calculate the magnetic field at the center of a circular loop

Using formula of magnetic field

B = \dfrac{I\mu_{0}}{2r}

Where, I = current

r = radius

Put the value into the formula

B =\dfrac{2.0\times4\pi\times10^{-7}}{2\times4.0\times10^{-2}}

B =0.00003141\ T

B=3.14\times10^{-5}\ T

Hence, The magnetic field at the center of a circular loop is 3.14\times10^{-5}\ T.

7 0
3 years ago
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