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Alexxx [7]
3 years ago
6

A molten sample of 1.00kg of iron with a specific heat of 0.385J/g.K at 1000.K is immersed in a sample of water. If the water ab

sorbs 270 kJ of heat what is the final temperature of the iron?
Chemistry
1 answer:
Schach [20]3 years ago
6 0

Answer:

Final T = 298.7K

Explanation:

In this problem, the heat given for the iron is equal to the heat that water absorbs. Using the equation:

Q = C*m*ΔT

<em>Where Q is heat given = 270000J</em>

<em>C is specific heat of substance = 0.385J/gK</em>

<em>m is mass of iron = 1000g</em>

<em>ΔT is change in temperature = Initial temperature - Final temperature.</em>

<em />

270000J = 0.385J/gK*1000g*(1000K-Final temperature)

701.3J/K = 1000K - Final T

<h3>Final T = 298.7K</h3>
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What is the temperature of a water body containing a 90% saturation and 11.5 ppm of dissolved oxygen?
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Using the chart that has been provided, we may determine water temperature. We do this by drawing a straight line form the bottom scale which has the ppm of oxygen dissolved to the middle scale which has the percentage saturation.

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4 years ago
A cylinder with a moving piston expands from an initial volume of 0.250 L against an external pressure of 2.00 atm. The expansio
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Answer:

The final volume of the cylinder is 1.67 L

Explanation:

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external pressure = 2.00 atm

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Step 2: Definition of reversible work:

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V2 = (-Wrev/P)  + V1

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8 0
3 years ago
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