How much heat is needed to raise the temperature of 28g of water to 74 Celsius

A scientist crosses a rabbit with short fur and a rabbit with long fur. which of these outcomes would show that the trait for fu

maks197457 [2]

Answer:

d. all of the offspring have medium length fur.

Explanation:

Incomplete dominance is a phenomenon in which offspring produce a trait that is intermediate between the two forms of a certain trait.

For example: In four o clock plant, some plants produce red flowers while some plants produce white flowers. When plants with red flowers are crossed with plants with white flowers, all the offspring have pink flowers.

Why is that so?

This is because no allele is completely dominant over the other and therefore both contribute their individual effect by producing intermediate phenotype.

Example in question:

Cross between a rabbit with short fur (SS) and a rabbit with long fur (LL)

P1: SS x LL

Gametes: S and L

Offspring SL :SL

SL: Medium length fur

Therefore this is a case of incomplete dominance.

Hope it help!

7 0

3 years ago

What does muscle tissue do?

Oliga [24]

Muscle tissue is the outer layer that protects your muscles and helps them to move without falling off.

4 0

2 years ago

In a hardy-weinberg population with two alleles, a and a, that are in equilibrium, the frequency of the allele a is 0. 3. What i

zavuch27 [327]

Here, given-

homozygous alleles 'a' have a frequency of 0.3.

Also the alleles are in equilibrium in a Hardy-Weinberg population. The frequency of individuals that are homozygous for this allele are= 0.49.

The Hardy-Weinberg equilibrium can be defined as the principle which states that the variation in the genetic makeup of a population remains constant and unchanged till there are no external interferences, influencing the population.

Calculation-

$p + q = 1\\0.3 + q= 1\\q= 1- 0.3\\\\q= 0.7$

Then to find the frequency of the individuals homozygous for this allele the following formula needs to be used-

$p^{2} + 2pq + q^{2} =1$

$p^{2} = dominant homozygous frequency\\2pq= heterozygous frequency\\q^{2} = recessive homozygous frequency\\$

Thus, the individuals homozygous for the allele can be calculated by $q^{2} = (0.7)^{2} \\= 0.49$

Learn more about the Hardy-Weinberg equilibrium here-

brainly.com/question/16823644

#SPJ4

4 0

2 years ago

What would happen if a disease killed off the top level of an ecosystem?

Daniel [21]

If it killed the top level of an ecosystem it would damage the whole ecosystem because it's connected. An organism depends on that top organism which would mean that is that organism dies it would affect the organism that depends on it.

4 0

3 years ago

Thermus and Deinococcus A. survive in extreme environments.B. are both thermophilic.C. are both radiation resistant.D. both serv

attashe74 [19]

Answer:

Option a, survive in extreme environments

Explanation:

Both Thermus and Deinococcus belong to the group of bacteria that are collectively termed as Deinococcus–Thermus group.

Deinococcus are radiation-resistant vegetative cell as they are able to resist ionising radiation. Also some species of Deinococcus are thermophile.

Thermus are thermophilic bacteria that are able to live in extreme temperature condition and thus are able to tolerate high temperature.

Hence, option A is correct.

3 0

3 years ago