<span>the loss of one or more electrons & the addition of one of more electrons</span>
Answer:
a) 0.13 bar
b) 5.05 L
Explanation:
Let us take the mass of the mixture to be 100 g. Hence, 70% by weight of dioxygen corresponds to 70 g
Mass of dihydrogen = 100g - 70 g = 30g
Number of moles of dioxygen = 70g/32 g/mol = 2.2 moles of dioxygen
Number of moles of dihydrogen = 30g/2g/mol = 15 moles of dihydrogen
Total number of moles = 2.2 + 15 = 17.2 moles
Mole fraction of dioxygen = 2.2/17.2 = 0.13
Partial pressure = mole fraction * total pressure
Partial pressure of dioxygen = 0.13 * 1 = 0.13 bar
ii) number of moles in 8.8 g of CO2 = 8.8g/44g/mol = 0.2 moles
T = 31.1 + 273 = 304.1 K
P = 1 bar
V= ?
R = 0.083 bar L K-1 mol-1
From
PV=nRT
V = nRT/P
V= 0.2 * 0.083 * 304.1/1
V= 5.05 L
Answer:
cylinder A has a higher density then cylinder B or more accurately the liquid in cylinder A is denser then the liquid in the second tube.
Explanation:
"Denser" simply means more matter is contained in the same space for example say you fill a tank with helium and another tank with water. Although they are the same size one will weigh much more because their is more particles or "stuff" inside the same area this can be because of a few things one it can be because the atoms or elements that compose the substance are heavier containing more electrons and protons in their orbit. or the molecular structure is more compact like a chicken wire fence has more wire in it then a barbed wire wire fence covering the same area because of the grid of wire in the middle.
Answer:
Acetylene: -1,256 kJ/mol
Ethanol: -1,277 kJ/mol
The combustion of 0.25 mol of an unknown organic compound results in the release of 320 kJ of energy. Which of the compounds in the table could be the unknown compound?- Answer: Ethanol
N(Mg) : n(O)
1 : 1
the ratio is one to one