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Juliette [100K]
3 years ago
5

Look online for the growth of the trunk of a tree. Estimate how much time does it take for a water oak to grow one inch in diame

ter. Estimate the growth rate over a year.
Physics
1 answer:
Pavel [41]3 years ago
8 0

Answer:

8 months needed to grow one inch in diameter by water oak and it grows 24 inches of height in a year.

Explanation:

In 2 different ways the trunk of a tree grows first the height than second in diameter usually in diameter tree grows one ring per year. We can say on counting the number of rings we can determine the age of a tree both of the growth does not occur in the same rate.

Tree grows more higher as compared to the  diameter growth and mature trees usually grows 1 inch in diameter every year.

Water oak gets 24 inches height growth every year and   1.5 inch growth in diameter annually means if we divide 1.5 inches by 12 months we gets 0.125 inches growth monthly.so we can say 8 months are needed to grow the diameter of water oak 1 inch.

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Find the current passing through each of the 3 resistors connected parallel to each other as shown in the figure (i1, i2, I3). S
Thepotemich [5.8K]

Answer:

I1 = ε/R1

I2 = ε/R2

I3 = ε/R3

Explanation:

From the image, we see that the resistors are connected in parallel. This means that the voltage passing through them is the same.

Now, formula for current is; I = V/R

In this case, V which is voltage is denoted by ε.

Thus;

I1 = ε/R1

I2 = ε/R2

I3 = ε/R3

3 0
3 years ago
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Bingel [31]

Answer:

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7 0
3 years ago
1. Say whether the following statements are true or false and explain why:
tiny-mole [99]

Explanation:

A] TRUE

B] TRUE

C] FALSE

D] FALSE

E] TRUE

F] TRUE

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H] FALSE

8 0
3 years ago
When water freezes, its volume increases by 9.05% (that is, equation). What force per unit area is water capable of exerting on
PIT_PIT [208]

Answer:

1.991 × 10^(8) N/m²

Explanation:

We are told that its volume increases by 9.05%.

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To find the force per unit area which is also pressure, we will use bulk modulus formula;

B = Δp(V_o/ΔV)

Making Δp the subject gives;

Δp = B(ΔV/V_o)

Now, B is bulk modulus of water with a value of 2.2 × 10^(9) N/m²

Thus;

Δp = 2.2 × 10^(9)[0.0905]

Δp = 1.991 × 10^(8) N/m²

3 0
2 years ago
A sample of an ideal gas has a volume of 2.37 L at 2.80×102 K and 1.15 atm. Calculate the pressure when the volume is 1.68 L and
iogann1982 [59]

Answer:

p_2 = 1.76 atm

Explanation:

given data:

v_1 = 2.37 L

v_2 = 1.68 L

p_1 =1.15 atm

p_2 = ?

t_1 = 280 K

t_2 = 304 K

from Gas Law Equation

, WE HAVE

\frac{p_1 v_1}{t_1} =\frac{p_2 v_2}{t_2}

Putting the values

\frac{1.15*2.37}{280}  =\frac{p_2 *1.68}{304}

9.733*10^{-3} = \frac{p_2 *1.68}{304}

9.733*10^{-3}*304 = p_2*1.68

\frac{9.733*10^{-3}*304}{1.68} =p_2

p_2= 1.76 atm

7 0
3 years ago
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