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iVinArrow [24]
3 years ago
9

A 4.0 kg model rocket is launched, shooting 50.0 g of burned fuel from its exhaust at an average velocity of 625 m/s. What is th

e velocity of the rocket after the fuel has burned?
Physics
1 answer:
Scorpion4ik [409]3 years ago
8 0

Answer:

Velocity of rocket will be equal to 7.81 m/sec

Explanation:

We have given mass of the rocket m_1=4kg

Mass of fuel is given m_2=50gram=0.05kg ( As 1 kg is equal to 1000 gram )

Velocity of fuel v_2 = 625 m/sec

We have to find the velocity of rocket v_1

From conservation of momentum we know that initial momentum is equal to final momentum '

So m_1v_1=m_2v_2, here m_1 is mass of rocket v_1 is velocity of rocket m_2 is mass of fuel and v_2 is velocity of fuel

So 4\times v_1=625\times 0.05

v_1=7.81m/sec

So velocity of rocket will be equal to 7.81 m/sec

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Therefore, the correct answer is option D) complete.

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Calculate the capacitance of a system that stores 9.4 x 10-10 C of charge at
pantera1 [17]

The capacitance of the system is 1.9\cdot 10^{-11}F

Explanation:

The capacitance of a capacitor is given by the following equation:

C=\frac{Q}{V}

where

C is the capacitance

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V is the potential difference across the capacitor

In this problem, we have:

Q=9.4\cdot 10^{-10}C is the charge stored

V=50.0 V is the potential difference across it

Substituting into the equation, we find the capacitance:

C=\frac{9.4\cdot 10^{-10}}{50.0}=1.9\cdot 10^{-11}F

Learn more about capacitors:

brainly.com/question/10427437

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7 0
3 years ago
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A disk has a radius of 30 cm and a mass of 0.3 kg and is turning at 3.0 rev/s. A trickle of sand falls onto the disk at a distan
Pani-rosa [81]

Answer:

The mass of the sand that will fall on the disk to decrease the is 0.3375 kg

Explanation:

Moment before = Moment after

I \omega_i = I \omega_f +mr^2 \omega_f\\\\mr^2 \omega_f = I \omega_i  - I \omega_f \\\\m = \frac{ I \omega_i  - I \omega_f}{r^2 \omega_f }

where;

I is moment of inertia = Mr² = 0.3 x (0.3)² = 0.027 kg.m²

substitute this in the above equation;

m = \frac{ 0.027[3(2 \pi)  - 2(2 \pi)]} {0.2^2 * 6\pi } = \frac{ 0.027[6 \pi  - 4\pi]} {0.2^2 * 4\pi }\\\\m = 0.3375kg

Therefore, the mass of the sand that will fall on the disk to decrease the is 0.3375 kg

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