Ask question

Ask question

All categories

3 years ago

9

A 4.0 kg model rocket is launched, shooting 50.0 g of burned fuel from its exhaust at an average velocity of 625 m/s. What is th

e velocity of the rocket after the fuel has burned?

1 answer:

Scorpion4ik [409]3 years ago

8 0

Answer:

Velocity of rocket will be equal to 7.81 m/sec

Explanation:

We have given mass of the rocket $m_1=4kg$

Mass of fuel is given $m_2=50gram=0.05kg$ ( As 1 kg is equal to 1000 gram )

Velocity of fuel $v_2$ = 625 m/sec

We have to find the velocity of rocket $v_1$

From conservation of momentum we know that initial momentum is equal to final momentum '

So $m_1v_1=m_2v_2$ , here $m_1$ is mass of rocket $v_1$ is velocity of rocket $m_2$ is mass of fuel and $v_2$ is velocity of fuel

So $4\times v_1=625\times 0.05$

$v_1=7.81m/sec$

So velocity of rocket will be equal to 7.81 m/sec

You might be interested in

A tin can has a volume of 1100 cm³ and a mass of 80 g. Approximately how many grams of lead shot can it carry without sinking in

Kruka [31]

Answer:

1020g

Explanation:

Volume of can= $1100cm^3=1100\times 10^{-6}m^3$

$1cm^3=10^{-6}m^3$

Mass of can=80g= $\frac{80}{1000}=0.08kg$

1Kg=1000g

Density of lead= $11.4g/cm^3=11.4\times 10^{3}=11400kg/m^3$

By using $1g/cm^3=10^3kg/m^3$

We have to find the mass of lead which shot can it carry without sinking in water.

Before sinking the can and lead inside it they are floating in the water.

Buoyancy force = $F_b=Weight of can+weight of lead$

$\rho_wV_cg=m_cg+m_lg$

Where $\rho_w=10^3kg/m^3=$ Density of water

$m_c=$ Mass of can

$m_l=$ Mass of lead

$V_c=$ Volume of can

Substitute the values then we get

$1000\times 1100\times 10^{-6}=0.08+m_l$

$1.1-0.08=m_l$

$m_l=1.02 kg=1.02\times 1000=1020g$

$1 kg=1000g$

Hence, 1020 grams of lead shot can it carry without sinking water.

4 0

3 years ago

Why are black holes considered the "destroyers and creators" of life? A. Black holes play a role in the formation of galaxies th

bezimeni [28]

Answer:

A

Explanation:

A is just the most logical. Sagittarius doesn't mean anything here.

Light does not originate anywhere. DNA is not formed in a black hole.

6 0

3 years ago

Do houses use parallels or series circuits

Vilka [71]

Every electrical outlet in your house, and every device or appliance that's
plugged into an outlet, are all in parallel. It's also most likely that all of yours
are in parallel with all the outlets, devices, and appliances in the homes or
apartments of a few of your neighbors.

The only things in your home that are connected in series are the switches
that turn things on and off.

3 0

3 years ago

Read 2 more answers

A 3.00-kg object has a velocity 1 6.00 i ^ 2 2.00 j ^2 m/s. (a) what is its kinetic energy at this moment? (b) what is the net w

tatyana61 [14]

(a) The velocity of the object on the x-axis is 6 m/s, while on the y-axis is 2 m/s, so the magnitude of its velocity is the resultant of the velocities on the two axes:
$v= \sqrt{(6.00m/s)^2+(2.00 m/s)^2}=6.32 m/s$
And so, the kinetic energy of the object is
$K= \frac{1}{2}mv^2= \frac{1}{2}(3.00 kg)(6.32 m/s)^2=60 J$

(b) The new velocity is 8.00 m/s on the x-axis and 4.00 m/s on the y-axis, so the magnitude of the new velocity is
$v= \sqrt{(8.00 m/s)^2+(4.00 m/s)^2}=8.94 m/s$
And so the new kinetic energy is
$K= \frac{1}{2}mv^2= \frac{1}{2}(3.00 kg)(8.94 m/s)^2=120 J$

So, the work done on the object is the variation of kinetic energy of the object:
$W=\Delta K=120 J-60 J=60 J$

7 0

3 years ago

a car advertisement states that a certain car that Emily miller loves can accelerates from rest to 70 km/h in 7 seconds. find th

vova2212 [387]

10 km/1 second. Is this what you mean?..

7 0

4 years ago

Read 2 more answers