Answer:
Explanation:
Given
radius of circular path
Position is given by
Differentiate 1 to angular velocity we get
Differentiate 2 to get angular acceleration
Net acceleration is the vector summation of tangential and centripetal force
Ionic bonds are formed between a cation (metal) and an anion (nonmetal)
Answer:
The tangential speed of the ball is 11.213 m/s
Explanation:
The radius is equal:
(ball rotates in a circle)
If the system is in equilibrium, the tension is:
![Tcos70=mg\\Tsin70=\frac{mv^{2} }{r}](https://tex.z-dn.net/?f=Tcos70%3Dmg%5C%5CTsin70%3D%5Cfrac%7Bmv%5E%7B2%7D%20%7D%7Br%7D)
Replacing:
![\frac{mg}{cos70} sin70=\frac{mv^{2} }{r} \\Clearing-v:\\v=\sqrt{rgtan70}](https://tex.z-dn.net/?f=%5Cfrac%7Bmg%7D%7Bcos70%7D%20sin70%3D%5Cfrac%7Bmv%5E%7B2%7D%20%7D%7Br%7D%20%5C%5CClearing-v%3A%5C%5Cv%3D%5Csqrt%7Brgtan70%7D)
Replacing:
![v=\sqrt{2.161x^{2}*9.8*tan70 } =11.213m/s](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B2.161x%5E%7B2%7D%2A9.8%2Atan70%20%7D%20%3D11.213m%2Fs)
Answer:
s = 30330.7 m = 30.33 km
Explanation:
First we need to calculate the speed of sound at the given temperature. For this purpose we use the following formula:
v = v₀√[T/273 k]
where,
v = speed of sound at given temperature = ?
v₀ = speed of sound at 0°C = 331 m/s
T = Given Temperature = 10°C + 273 = 283 k
Therefore,
v = (331 m/s)√[283 k/273 k]
v = 337 m/s
Now, we use the following formula to calculate the distance traveled by sound:
s = vt
where,
s = distance traveled = ?
t = time taken = 90 s
Therefore,
s = (337 m/s)(90 s)
<u>s = 30330.7 m = 30.33 km</u>
Explanation:
<u>Formula:</u>
![velocity = (d \div t)](https://tex.z-dn.net/?f=velocity%20%3D%20%28d%20%5Cdiv%20t%29)
<u>d = distance given</u>
<u>t</u><u> </u><u>=</u><u> </u><u>the amount of time </u><u>given</u>
<u>Substitute the given values into the formula for velocity</u><u>:</u>
![v = 8 \div 4](https://tex.z-dn.net/?f=v%20%3D%208%20%5Cdiv%204)
velocity is shortened for v.
8 (distance) divided by 4 (time) equals the velocity.
<u>Solve:</u>
![2 = 8 \div 4](https://tex.z-dn.net/?f=2%20%3D%208%20%5Cdiv%204)
The velocity of the toy car equals: B. 2 m/s.