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when we placed in the container of real depth assuming = d
if the container filled with liquid A then its apparent depth d' = 7cm
so the refractive index nA = real depth / apparent depth
= d/7cm = 0.1428d
if the container filled with liquid B then its apparent depth d' = 6cm
so the refractive index nB = real depth / apparent depth
= d/6cm = 0.166d
if the container filled with liquid C then its apparent depth d' = 5cm
so the refractive index nC = real depth / apparent depth
= d/5cm = 0.2d
Since the refractive index is inversely proportional to the apparent depth
then the refractive indices are nC > nB > nA
Answer:
15.625 watts
Explanation:
Recall that power is defined as the worked performed per unit of time:
Power = Work / time
The work done is Force * distance, so in our case the work is:
Work = 25 M * 5 m = 125 J
Then the power will be:
Power = 125 J / 8 sec = 15.625 watts
Explanation:
First, simplify the circuit. Then calculate the parallel and consecutive resistances to find the answer.
