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shutvik [7]
3 years ago
12

A multi-dimensional being reaches down to Earth and pulls you out of the universe. You are then thrown back into the universe at

a place and time of the being's choosing, and you are permitted to leave only after you have identified your surroundings. This process is repeated several times. Through a scientifically unexplainable miracle, you are able to survive in every one of the places that you find yourself. In each scenario below, identify your surroundings (and potentially your cosmic era) from among the choices given. You find yourself in a place that is unimaginably hot and dense. A rapidly changing gravitational field randomly warps space and time. Gripped by these huge fluctuations, you notice that there is but a single, unified force governing the universe.
Required:
Where are you?
Physics
1 answer:
Shkiper50 [21]3 years ago
5 0

You are in an early universe.

In the study of the evolution of the universe, it has been determined before Plank time (before the big bang and right after it), the early universe had the following characteristics:

  • There was only one single force acting over all that existed.
  • The early universe was very hot and dense because all matter had contracted before the big bang.
  • Space and time were wrapped.

These characteristics match the ones described, based on this, we can conclude you are in an early universe.

Learn more about universe in: brainly.com/question/9724831

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The synodic period for a planet is different from its sidereal period because
IrinaK [193]
<span>Earth (and hence the observer) moves.</span>
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3 years ago
A force of 9 pounds stretches a spring 1 foot. A mass weighing 6.4 pounds is attached to the spring, and the system is then imme
mart [117]

Answer:

\frac{d^2x}{dt^2}+\frac{\beta}{m}\frac{dx}{dt}+\frac{k}{m}x=0

Explanation:

let m be the mass attached, let k be the spring constant and let \beta be the positive damping constant.

-By Newton's second law:

m\frac{d^2x}{dt^2}=-kx-\beta \frac{dx}{dt}

where x(t) is the displacement from equilibrium position. The equation can be transformed into:

\frac{d^2x}{dt^2}+\frac{\beta}{m}\frac{dx}{dt}+\frac{k}{m}x=0  shich is the equation of motion.

7 0
3 years ago
This is heat transfer due to differences in density
Gala2k [10]

Answer:

convection

Explanation:

Heat transfer by convection is caused by differences of temperature and density within a fluid.

8 0
3 years ago
Read 2 more answers
Please need help on this not too sure on this
n200080 [17]

Answer:

the last one

Explanation:

Because it is a magnifying glass, it magnifies the object and makes it bigger than it appears

3 0
3 years ago
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Calculate the de Broglie wavelength of (a) a mass of 1.0 g traveling at 1.0 m s−1 , (b) the same, traveling at 1.00 × 105 km s−1
lesantik [10]

Answer:

a)\lambda=6.63\times10^{-31}m

b)\lambda=6.63\times10^{-39}m

c)\lambda=9.97\times10^{-11}m

d)\lambda=4.03\times10^{-36}m

e)λ=∞

Explanation:

De Broglie discovered that an electron or other mass particles can have a wavelength associated, and that wavelength (λ) is:

\lambda=\frac{h}{P}=\frac{h}{mv}

with h the Plank's constant (6.63\times10^{-34}\frac{m^{2}kg}{s}) and P the momentum of the object that is mass (m) times velocity (v).

a)\lambda=\frac{6.63\times10^{-34}}{(1.0\times10^{-3}kg*1.0)}

\lambda=6.63\times10^{-31}m

b)\lambda=\frac{6.63\times10^{-34}}{(1.0\times10^{-3}*(1.00\times10^{8}))}

\lambda=6.63\times10^{-39}m

c)\lambda=\frac{6.63\times10^{-34}}{(6.65\times10^{-27}*1000)}

\lambda=9.97\times10^{-11}m

d)\lambda=\frac{6.63\times10^{-34}}{(74*2.22)}

\lambda=4.03\times10^{-36}m

e) \lambda=\frac{6.63\times10^{-34}}{(74*0)}

λ=∞

6 0
3 years ago
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