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arsen [322]
2 years ago
10

which properties change the composition of a substance? A) physical properties B) neither chemical nor physical properties C) ch

emical properties D) Chemical and physical properties​
Physics
1 answer:
svlad2 [7]2 years ago
8 0

Answer:

C) chemical properties is the answer....

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The hydraulic cylinder imparts a constant upward velocity vA = 0.23 m/s to corner A of the rectangular container during an inter
s344n2d4d5 [400]

Answer:

vB = 0.5418 m/s (→)

aB = - (0.3189/L)  m/s²

ωcd = (0.2117/L)  rad/s

Explanation:

a) Given:

vA = 0.23 m/s (↑) (constant value)

If

tan θ = vA/vB

For the instant when θ = 23° we have

vB = vA/ tan θ

⇒ vB = 0.23 m/s/tan 23°

⇒ vB = 0.5418 m/s (→)

b) If tan θ = vA/vB   ⇒   vA = vB*tan θ

⇒  d(vA)/dt = d(vB*tan θ)/dt

⇒  0 = tan θ*d(vB)/dt + vB*Sec²θ*dθ/dt

Knowing that  

aB = d(vB)/dt

ωcd = dθ/dt

we have

⇒  0 = tan θ*aB + vB*Sec²θ*ωcd

ωcd = - Sin (2θ)*aB/(2*vB)

If

v = ωcd*L

where v = vA*Cos θ   ⇒  ωcd = v/L = vA*Cos θ/L

⇒ vA*Cos θ/L = - Sin (2θ)*aB/(2*vB)

⇒ aB = - vA*vB/((Sin θ)*L)

We plug the known values into the equation

aB = - (0.23 m/s)*(0.5418 m/s)/(L*Sin 23°)

⇒ aB = - (0.3189/L)  m/s²

Finally we obtain the angular velocity of CD as follows

ωcd = vA*Cos θ/L

⇒ ωcd = 0.23 m/s*Cos 23°/L

⇒ ωcd = (0.2117/L)  rad/s

5 0
3 years ago
In which of the following cases is the torque about the shoulder due to the weight of the arm the greatest? Case 1: A person hol
Alexeev081 [22]

Answer: a) Case 2 b) Case 1

Explanation:

a) By definition, the magnitude of a torque, referred to a given point, is expressed as the product of the force that causes the torque, times the perpendicular distance to the reference point.

If we assume that the only force acting on the arm is the weight of the arm, and that this is concentrated in a point in the center of it (taking the arm as a solid bar with the center of mass at the mid-point), clearly the torque will be the greatest when the force be exactly perpendicular, which is the case of the arm placed straight out parallel to the ground (Case 2).

b)  As the torque and the angular acceleration are directly proportional each other (being the rotational inertia the proportionality constant) the angular acceleration will be maximum when torque be maximum also, which is the case that the arm begins to swim, due to the perpendicular distance to the shoulder is the maximum possible (Case 1).

6 0
3 years ago
1. A 59 kg person is in a vehicle travelling at 41 m/s. The vehicle runs into a telephone pole. At impact, it
Tems11 [23]

Answer:

a. 12,600 N

b. 1290 kg

Explanation:

a. Impulse = change in momentum

F Δt = m Δv

F (0.192 s) = (59 kg) (0 m/s − 41 m/s)

F = -12,600 N

b. F = mg

12,600 N = m (9.8 m/s²)

m = 1290 kg (or 2,830 lbs)

5 0
3 years ago
Suppose you have a dipole that's free to move in any way (including rotate - imagine it floating in space). And there's an objec
Setler [38]

Complete Question

The complete question shown on the first uploaded image

Answer:

a)

The force on Q due to dipole is Attractive

b)

The charge Q exerts attractive force on the dipole

c)

Yes from the above parts, force depends on the sign of charge

d)

   F = kQq[\frac{d^{2}+2rd}{r^{2}(d+r)^{2}} ]

e)

The magnitude o force decrease by a factor of 8.0 times

Explanation:

The explanation is shown on the second uploaded image

5 0
2 years ago
What is the term for an area of a country located away from capital?
8090 [49]
Province. Is what is located away from the capital.
5 0
3 years ago
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