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dimaraw [331]
4 years ago
13

What is the energy needed to raise 2.004g of water from 89.0°C to 139.0°C?

Chemistry
1 answer:
gulaghasi [49]4 years ago
6 0

Answer:

The answer to your question is E = 419.435 J

Explanation:

Data

Mass = m = 2.004 g

Temperature 1 = T1 = 89°C

Temperature 2 = T2 = 139°C

Specific heat  of water = Cp = 4.186 J/g°C

Energy = E = ?

Formula

E = mCp(T2 - T1)

Substitution

E = (2.004)(4.186)(139 - 89)

Simplification and result

E = 8.3887(50)

E = 419.435 J

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A gram of gasoline produces 45 kJ of energy when burned. Gasoline has a density of 0.77 g/mL. How would you calculate the amount
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4 0
3 years ago
1. Calculate how many moles of glycine are in a 130.0-g sample of glycine.2. Calculate the percent nitrogen by mass in glycine.
Alexxx [7]

Answer:

n=1.732mol

\% N=18.7\%

Explanation:

Hello!

In this case, since the molecular formula of glycine is C₂H₅NO₂, we realize that the molar mass is 75.07 g/mol; thus, the moles in 130.0 g of glycine are:

n=130.0g*\frac{1mol}{75.07 g}\\\\ n=1.732mol

Furthermore, we can notice 75.07 grams of glycine contains 14.01 grams of nitrogen; thus, the percent nitrogen turns out:

\% N=\frac{14.01}{75.07}*100\% \\\\\% N=18.7\%

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4 0
3 years ago
What would you need to do to calculate the molality of 10 g of NaCl in 2 kg of
jasenka [17]

Answer:

O B. Convert the 10 g of NaCl to moles of NaCl.

Explanation:

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58.44 is the molar mass of NaCl

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4 0
3 years ago
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