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ryzh [129]
3 years ago
9

PLEASE HELPPPP!!!!!

Chemistry
1 answer:
Likurg_2 [28]3 years ago
6 0

Answer : The mass of nitric acid is, 214.234 grams.

Solution : Given,

Moles of nitric acid = 3.4 moles

Molar mass of nitric acid = 63.01 g/mole

Formula used :

\text{Mass of }HNO_3=\text{Moles of }HNO_3\times \text{Molar mass of }HNO_3

Now put all the given values in this formula, we get the mass of nitric acid.

\text{Mass of }HNO_3=(3.4moles)\times (63..01g/mole)=214.234g

Therefore, the mass of nitric acid is, 214.234 grams.


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Explanation:

Complete question is

You are asked to pre pare a pH = 4.00 buffer starting from 1.50 L of 0.0200 M solution of benzoic acid

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Solution

Given

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log \frac{C6H5COONa}{C6H5COOH}  = 4 + log (6.3 * 10^ {-5})\\log \frac{C6H5COONa}{C6H5COOH}  = -0.20\\\frac{C6H5COONa}{C6H5COOH} = 10^{-0.2}\\{C6H5COONa} = 10^{-0.2} * 0.02\\{C6H5COONa} =  0.63 * 0.02\\{C6H5COONa} =  0.0126 M

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