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PtichkaEL [24]
3 years ago
7

Calculate the energy required to heat 566.0mg of graphite from 5.2°C to 23.2°C. Assume the specific heat capacity of graphite un

der these conditions is ·0.710J·g−1K−1 . Be sure your answer has the correct number of significant digits.
Chemistry
1 answer:
maw [93]3 years ago
6 0

Answer:

7.23 J

Explanation:

Step 1: Given data

  • Mass of graphite (m): 566.0 mg
  • Initial temperature: 5.2 °C
  • Final temperature: 23.2 °C
  • Specific heat capacity of graphite (c): 0.710J·g⁻¹K⁻¹

Step 2: Calculate the energy required (Q)

We will use the following expression.

Q = c × m × ΔT

Q = 0.710J·g⁻¹K⁻¹ × 0.5660 g × (23.2°C-5.2°C)

Q = 7.23 J

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Perform the following conversions:<br> (a) 68°F (a pleasant spring day) to °C and K.
IgorC [24]

Converting  temperature of 68°F to °C gives 20 °C.

Converting  temperature of 68°F to K gives 293 K.

<h3>What is temperature conversion?</h3>

Temperature conversion is the process of converting  the measurement units of the temperature recorded in a particular unit to another unit.

The various units of Temperature include;

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<h3>Converting  68°F to °C</h3>

F = 1.8C + 32

(F - 32/1.8) = C

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<h3>Converting  20°C to K</h3>

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Learn more about temperature conversion here: brainly.com/question/23419049

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