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guapka [62]
4 years ago
6

The first method of determining the chemical composition of substances in space was to _____.

Chemistry
1 answer:
garik1379 [7]4 years ago
6 0
Analyze starlight transmitted to earth

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The transfer of a phosphate group to a molecule or compound is called The transfer of a phosphate group to a molecule or compoun
ki77a [65]

Answer:

Phosphorylation

Explanation:

Phosphorylation is the term used to describe the transfer of a phosphate group (PO34-) from a donor to a receptor molecule or compound. The process of phosphorylation is usually catalysed by a biological enzyme called KINASE.

Phosphorylation can either be addition of an inorganic phosphate to a molecule. For example, addition of phosphate group to ADP to form ATP, or the donation of a phosphate group to another molecule, e.g transfer of phosphate from ATP to glucose to form glucose-6-phosphate during glycolysis.

3 0
3 years ago
Which option identifies why Tony does NOT purchase the strawberries in the following scenario?
trapecia [35]

Answer:

He only purchases strawberries grown locally.

Explanation:

Based on the information we are given, this is the only reasonable answer.

3 0
3 years ago
Read 2 more answers
Which of the following molecules has a central atom with precisely two unshared
Sladkaya [172]
Yes it is pairs of electrons with two shared molecules
8 0
3 years ago
How many grams of Ca are contained in 113 mL of 0.52 M Ca (OH)2 solution
Kay [80]
<span>113 ml = 0.113L

0.52M = 0.52 mol/L

(0.52 mol/L) x 0.113L = 0.059 mol x (molar mass of Ca) = your answer. </span>
8 0
3 years ago
A 0.1873 g sample of a pure, solid acid, h2x was dissolved in water and titrated with 0.1052 m naoh solution. the balanced equat
belka [17]
According to the balanced equation of the reaction:
H2X (aq) +2 NaOH (aq) → Na2X (aq) + 2H2O(l)

First, we have to get the no. of moles of H2X:
no.of moles of H2X = weight / molar mass
when we have the H2X weight = 0.1873 g & the molar mass H2X = 85 g/mol
So by substitution:
∴ no.of moles of H2X = 0.1873 /85
                                     = 0.0022 mol
-then, we need to get no.of moles of NaOH:
from the balanced equation, we can see that 1 mol H2X = 2 mol NaOH
∴ no.of moles of NaOH = no.of moles of H2X *2
                                       = 0.0022 * 2 = 0.0044 mol
So we can get the volume per litre from this formula:
M (NaOH) = no.of moles NaOH / Volume L
So by substitution:
0.1052 = 0.0044 / Volume L
∴Volume = 0.042 L *1000 = 42 mL
5 0
3 years ago
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