The first method of determining the chemical composition of substances in space was to ____

Who discovered that geological changes are cyclical?

stich3 [128]

A. James Hutton

Hope this helps!

4 0

4 years ago

Helium is mixed with oxygen gas for deep-sea divers. Calculate the percent by volume of oxygen gas in the mixture if the diver h

kvasek [131]

Answer : The percent by volume of oxygen gas in the mixture is, 5.3 %

Explanation :

According to the Raoult's law,

$p^o_A=X_A\times p_A$

where,

$p_A$ = total partial pressure of solution = 3.8 atm

$p^o_A$ = partial pressure of oxygen = 0.20 atm

$X_A$ = mole fraction of oxygen = ?

Now put all the given values in this formula, we get:

$p^o_A=X_A\times p_A$

$0.20atm=X_A\times 3.8atm$

$X_A=0.0526$

Now we have to calculate the percent by volume of oxygen gas in the mixture.

The mole percent of oxygen gas = $0.0526\times 100=5.3\%$

As we know that, there is a direct relation between the volume of moles.

So, mole percent of oxygen gas = volume percent of oxygen gas

Volume percent of oxygen gas = $0.0526\times 100=5.3\%$

Therefore, the percent by volume of oxygen gas in the mixture is, 5.3 %

5 0

4 years ago

Lightning is very dangerous because it -

notsponge [240]

Did you ever get the awnser to this question cause im stuck on it too

3 0

3 years ago

Read 2 more answers

What is the equation if the product is CaOH+(aq)?

zavuch27 [327]

The product is called carbon monohydroxide (CaOH+) ion. This is the only product if the solution is alkaline. The reactants are calcium (Ca2+) and hydroxide (OH-) ions. If the solution is acidic, hydrogen (H+) ion is also included in the product side of the equation.

Ca2+(aq) + OH-(aq) -> CaOH+(aq)

7 0

3 years ago

The vapor pressure of ethanol is 1.00 × 102 mmHg at 34.90°C. What is its vapor pressure at 60.21°C? (ΔHvap for ethanol is 39.3 k

Delicious77 [7]

Answer:

The vapor pressure at 60.21°C is 327 mmHg.

Explanation:

Given the vapor pressure of ethanol at 34.90°C is 102 mmHg.

We need to find vapor pressure at 60.21°C.

The Clausius-Clapeyron equation is often used to find the vapor pressure of pure liquid.

$ln(\frac{P_2}{P_1})=\frac{\Delta_{vap}H}{R}(\frac{1}{T_1}-\frac{1}{T_2})$

We have given in the question

$P_1=102\ mmHg$

$T_1=34.90\°\ C=34.90+273.15=308.05\ K\\T_2=60.21\°\ C=60.21+273.15=333.36\ K\\\Delta{vap}H=39.3 kJ/mol$

And $R$ is the Universal Gas Constant.

$R=0.008 314 kJ/Kmol$

$ln(\frac{P_2}{102})=\frac{39.3}{0.008314}(\frac{1}{308.05}-\frac{1}{333.36})\\\\ln(\frac{P_2}{102})=4726.967(\frac{333.36-308.05}{333.36\times308.05})\\\\ln(\frac{P_2}{102})=4726.967(\frac{25.31}{333.36\times308.05})\\\\ln(\frac{P_2}{102})=4726.967(\frac{25.31}{102691.548})\\\\ln(\frac{P_2}{102})=1.165$

Taking inverse log both side we get,

$\frac{P_2}{102}=e^{1.165}\\\\P_2=102\times 3.20\ mmHg\\P_2=327\ mmHg$

8 0

3 years ago

The first method of determining the chemical composition of substances in space was to _____.