Answer:
我實際上不知道答案，我只是為了點數而這樣做，哈哈，祝你好運哈哈
Explanation:
我實際上不知道答案，我只是為了點我實際上不知道答案，我只是為了點數而這樣做，哈哈，祝你好運哈哈數而這樣做，哈哈，祝你好運哈哈
Answer: The equilibrium constant for the given reaction is 0.0421.
Explanation:
Concentration of ![[PCl_5]](https://tex.z-dn.net/?f=%5BPCl_5%5D)
= 0.0095 M
Concentration of ![[PCl_3]](https://tex.z-dn.net/?f=%5BPCl_3%5D)
= 0.020 M
Concentration of ![[Cl_2]](https://tex.z-dn.net/?f=%5BCl_2%5D)
= 0.020 M
The expression of the equilibrium constant is given as:
![K_c=\frac{[PCl_3][Cl_2]}{[PCl_5]}=\frac{0.020 M\times 0.020 M}{0.0095 M}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BPCl_3%5D%5BCl_2%5D%7D%7B%5BPCl_5%5D%7D%3D%5Cfrac%7B0.020%20M%5Ctimes%200.020%20M%7D%7B0.0095%20M%7D)
(An equilibrium constant is an unit less constant)
The equilibrium constant for the given reaction is 0.0421.
Answer:
120 g of NaCl in 300 g H20 at 90 C
Explanation:
At x = 90 go vertical to the line for NaCl...then go left to the y-axis to find the solubility in 100 g H20 = 40
we want 300 g H20 so multiply this by 3 to get 120 gm of NaCl in 300 g
Answer:
4.56 X 10^ -4 g/mL
Explanation:
A solution is prepared by diluting 6.0 mL of a 7.6 x 10-4 g/mL solution to a total volume of 10.0 mL. Calculate the concentration of the dilute solution.
(7.6 X10^-4 gm/m L) x( 6.0 m L ) = 45.6 X 10^-4 g
this is dissolved )in 10 m L=45.6 X 10^-4 g/ 10
4.56 X 10^ -4 g/mL
check
6/10 =0.6
4.56/7.6 = o.,6
