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KIM [24]
3 years ago
12

Which planet has a distinctive red spot? A. Mercury B. Venus C. Jupiter D. Mars

Chemistry
2 answers:
Firdavs [7]3 years ago
3 0
Jupiter------------------------
sweet [91]3 years ago
3 0
C.............................Jupiter
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How much heat is required to change 100 g of ice (H2O) at 253 K to vapor (steam) at 393 K?
soldier1979 [14.2K]

<u>Answer:</u> The heat required will be 58.604 kJ.

<u>Explanation: </u>

To calculate the amount of heat required, we use the formula:

Q= m\times c\times \Delta T

Q= heat gained  or absorbed = ? J

m = mass of the substance = 100 g

c = heat capacity of water = 4.186 J/g ° C

Putting values in above equation, we get:

\Delta T={\text{Change in temperature}}=(393-253)K=140K=140^oC

Q=100g\times 4.186J/g^oC\times 140^oC

Q = 58604 Joules  = 58.604 kJ     (Conversion factor: 1 kJ = 1000J)

Thus, heat released by 100 grams of ice is 58.604kJ.

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3 years ago
Which of the following would you except to see in the death of a star that is less than 0.5 solar mass
Ket [755]

B. White Dwarf.

<h3>Explanation</h3>

The star would eventually run out of hydrogen fuel in the core. The core would shrink and heats up. As the temperature in the core increases, some of the helium in the core will undergo the triple-alpha process to produce elements such as Be, C, and O. The triple-alpha process will heat the outer layers of the star and blow them away from the core. This process will take a long time. Meanwhile, a planetary nebula will form.

As the outer layers of gas leave the core and cool down, they become no longer visible. The only thing left is the core of the star. Consider the Chandrasekhar Limit:

Chandrasekhar Limit: 1.4 \;M_\odot.

A star with core mass smaller than the Chandrasekhar Limit will not overcome electron degeneracy and end up as a white dwarf. Most of the outer layer of the star in question here will be blown away already. The core mass of this star will be only a fraction of its 0.5 \;M_\odot, which is much smaller than the Chandrasekhar Limit.

As the star completes the triple alpha process, its core continues to get smaller. Eventually, atoms will get so close that electrons from two nearby atoms will almost run into each other. By Pauli Exclusion Principle, that's not going to happen. Electron degeneracy will exert a strong outward force on the core. It would balance the inward gravitational pull and prevent the star from collapsing any further. The star will not go any smaller. Still, it will gain in temperature and glow on the blue end of the spectrum. It will end up as a white dwarf.

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2 years ago
Arrange the following atoms in order of decreasing atomic radius
ElenaW [278]

Answer:

li

be

na

si

s

............. ..

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A blood test shows clumps only in wells containing anti-A and anti-B antibodies. The Rhesus test was negative. Which is the corr
enyata [817]
The correct blood type is AB-
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A mole is known by what other name?
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Answer: avogadros number/constant

Explanation:

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