Answer:
The distance moved by the boat is 0.70 m.
Explanation:
Given that,
Mass of Romeo = 77.0 kg
Mass of Juliet = 55.0 kg
Distance = 2.70 m
Mass of boat = 80.0 kg
Let the distance moved by the boat is x.
as the center of mass will not change it's position
We need to calculate the distance moved by the boat
Using formula for distance
Put the value into the formula
Hence, The distance moved by the boat is 0.70 m.
Answer:
add a subscript of 4 after the O
Explanation:
The chemical formula of a compound is said to contain the elements in that compound with the respective number of atoms in each element. When writing chemical formula of a compound, the chemical symbols of each comprising element must be known. In this case involving Phosphorus tetraoxide, the symbols of the elements in this compound has been identified as P for Phosphorus and O for oxygen.
After identification of elemental symbols in the compound, Sebastian must now allocate the number of atoms that each element contains. According to the name of the compound, TETRA preceding oxygen means four (4), hence, four will be added as a subscript to O. Hence, at the end, the chemical formula will be PO4.
Please note that, the order of the chemical formula will go as the name implies Phosphorus tetraoxide, so phosphorus symbol (P) comes first, followed by oxygen symbol (O)
*Let north and east as positive direction.
1. a = +30 km / 2 hr
a = +15 km/hr
2. a = +45 km / 3 hr
a = +15 km/hr
3. a = -30 km / 1.5 hr
a = -20 km/hr
4. a = -25 km / 0.5 hr
a = -50 km/hr
speed = (15+15+20+50) / 4
= 25 km/hr
velocity:
(horizontal): (+15-50)= -35 km/hr
(vertical): (+15-20)= -5km/hr
v = sqrt(35^2 + 5^2)
v = 35.36 km/hr
I think the answer is d or b......
Answer:
M₁₂ = 1.01 10⁻⁴ H
, Fem = 3.54 10⁻³ V
Explanation:
The mutual inductance between two systems is
M₁₂ = N₂ Ф₁₂ / I₁
where N₂ is the number of turns of the inner solenoid N₂ = 21.0, i₁ the current that flows through the outer solenoid I₁ = 35.0 A / s and fi is the flux of the field of coil1 that passes through coil 2
the magnetic field of the coil1 is
B = μ₀ n I₁ = μ₀ N₁/l I₁
the flow is
Φ = B A₂
the area of the second coil is
A₂ = π d₂ / 4
Φ = μ₀ N₁ I₁ / L π d² / 4
we substitute in the first expression
M₁₂ = N₂ μ₀ N₁ / L π d² / 4
M₁₂ = μ₀ N₁ N₂ π d² / 4L
d = 0.170 cm = 0.00170 m
L = 4.00 cm = 0.00400 m
let's calculate
M₁₂ = 4π 10⁻⁷ 6750 21 π 0.0017²/ (4 0.004)
M₁₂ = π² 0.40966 10⁻⁷ / 0.004
M₁₂ = 1.01 10⁻⁴ H
The electromotive force is
Fem = - M dI₁ / dt
Fem = - 1.01 10⁻⁴ 35.0
Fem = 3.54 10⁻³ V