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SIZIF [17.4K]
2 years ago
9

A 2.98-kg object oscillates on a spring with an amplitude of 8.05 cm. Its maximum acceleration is 3.55 m/s2. Calculate the total

energy.
Physics
1 answer:
Aloiza [94]2 years ago
6 0

Answer:

a = ω^2 A      formula for max acceleration (ignoring sign)

V = ω A         formula for max velocity

V^2 = ω^2 A^2 = a A   from first equation

E = 1/2 M V^2 = 1/2 * 2.98 * 3.55 * .0805 = .426 J

(kg * m/sec^2 * m = kg m^2 / sec^2 = Joule

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What happens to the current as we increase the amount of stepping of our transformer? Does this help explain why the primary was
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Answer:

Current will decrease.

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2 years ago
Two identical 3.0-kg cubes are placed on a horizontal surface in
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<h3>What is frictional force?</h3>

When an object is moving on a rough surface, it experiences opposition. This opposing force is called the friction.

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Learn more about friction force.

brainly.com/question/1714663

#SPJ1

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