Each period corresponds to a principal energy level.
To get the theoretical yield of ammonia NH3:
first, we should have the balanced equation of the reaction:
3H2(g) + N2(g) → 2NH3(g)
Second, we start to convert mass to moles
moles of N2 = N2 mass / N2 molar mass
= 200 / 28 = 7.14 moles
third, we start to compare the molar ratio from the balanced equation between N2 & NH3 we will find that N2: NH3 = 1:2 so when we use every mole of N2 we will get 2 times of that mole of NH3 so,
moles of NH3 = 7.14 * 2 = 14.28 moles
finally, we convert the moles of NH3 to mass again to get the mass of ammonia:
mass of NH3 = no.moles * molar mass of ammonia
= 14.28 * 17 = 242.76 g
Answer:
By making observations and doing experiments
Answer:
Honestly, while Hydrogen appears to be in group 1, it really isn't. It is unique, and has no characteristics similar to others, especially to the alkali metals in group 1 and halogens in group 17.
Hydrogen only shares one thing with alkali metals. It has one electron in the outermost shell, and has a valency of one. As far as halogens go, Hydrogen is a reducing agent, and halogens are known for being oxidizing agents.
So, I can say that more research needs to be done on Hydrogen. In the meantime, it is quite unique. Thanks!