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3 years ago

11

Which best describe the isovolumetric contraction phase of the cardiac cycle?

2 answers:

cluponka [151]3 years ago

5 0

The name isovolumetric indicates that there is no change in volume that takes place and this only occurs when all of the valves within the heart are shut.

Zina [86]3 years ago

4 0

Isovolumentric contraction phase of the cardiac cycle is the stage at which isovolumentric contraction occurs, at this phase all of the four valves of the heart are closed.

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A 1.2 L weather balloon on the ground has a temperature of 25°C and is at atmospheric pressure (1.0 atm). When it rises to an el

icang [17]

Answer:

The temperature of the air at this given elevation will be 53.32425°C

Explanation:

We can calculate the final temperature through the combined gas law. Therefore we will need to know 1 ) The initial volume, 2 ) The initial temperature, 3 ) Initial Pressure, 4 ) Final Volume, 5 ) Final Pressure.

Initial Volume = 1.2 L ; Initial Temperature = 25°C = 298.15 K ; Initial pressure = 1.0 atm ; Final Volume = 1.8 L ; Final pressure = 0.73 atm

We have all the information we need. Now let us substitute into the following formula, and solve for the final temperature ( T $_2$ ),

P $_1$ V $_1$ / T $_1$ = P $_2$ V $_2$ / T $_2$ ,

T $_2$ = P $_2$ V $_2$ T $_1$ / P $_1$ V $_1$ ,

T $_2$ = 0.73 atm $*$ 1.8 L $*$ 298.15 K / 1 atm $*$ 1.2 L = ( 0.73 $*$ 1.8 $*$ 298.15 / 1 $*$ 1.2 ) K = 326.47425 K,

T $_2$ = 326.47425 K = 53.32425 C

7 0

2 years ago

Who invented the thermometer

Dvinal [7]

Gabriel Fahrenheit invented the thermometer

6 0

3 years ago

The distance from the sun to the earth would be which phrase best completes the sentence

Neporo4naja [7]

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3 years ago

Calculate the molar mass of a gas

spin [16.1K]

Answer:

MOLAR MASS = 32 g/mol

Explanation:

Condition of standard temperature and pressure(STP) are as follow:

Temperature = 273 K

Pressure = 1 atm (or 100000 Pa)

Here atm is atmosphere and Pa is Pascal

STP conditions arte used for measuring gas density and volume using Ideal Gas Law.Here 1 mole of ideal gas occupies 22.4 L of volume.

According toi Ideal Gas Equation :

PV = nRT

where P = pressure, n= number of moles, V = volume ,R= Ideal Gas Constant and T= temperature

$n=\frac{PV}{RT}$

From question:

V=280 ml = 0.28 L

P = 1 atm

R=0.08205 L atm/K mol

T=273 K

Putting values in above formula :

$n=\frac{1\times .280}{0.08205\times 273}$

n = 0.0125 moles

Now $n=\frac{given\ mass}{Molar\ mass}$

$Molar\ mass=\frac{given\ mass}{n}$

given mass = 0.4 g (given)

$Molar\ mass=\frac{0.4}{0.0125}$

On solving we get:

Molar mass = 32 g/mol

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KengaRu [80]

The answer will be 4

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3 years ago

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